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salantis [7]
3 years ago
10

During a medical evaluation, the doctor can __________.

Engineering
1 answer:
Elan Coil [88]3 years ago
8 0

Answer:

Treat the patient

i hope this is ur answer

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A site is compacted in the field, and the dry unit weight of the compacted soil (in the field) is determined to be 18 kN/m3. Det
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Answer:

the relative compaction is 105.88 %

Explanation:

Given;

dry unit weight of field compaction, W_d_{(field)} = 18 kN/m³

maximum dry unit weight measured, W_d_{(max)} = 17 kN/m³

Relative compaction (RC) of the site is given as the ratio of dry unit weight of field compaction and maximum dry unit weight measured

Relative compaction (RC) = dry unit weight of field compaction / maximum dry unit weight measured

RC = \frac{W_d_{(field)}}{W_d_{(max)}}

substitute the given values;

RC = \frac{18}{17} = 1.0588

RC (%) = 105.88 %

Therefore, the relative compaction is 105.88 %

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Vai trò của chủ đầu tư
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