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AVprozaik [17]
3 years ago
14

Explain your results: How can Earth’s gravity affect the water when the water isn’t actually touching the Earth? (2 pts) Do you

think the Moon’s gravity is affecting the water in the beaker? Why or why not? (2 pts) If you were on the Moon, do you think you would feel the pull of Earth’s gravity? Explain! (2 pts)
Physics
1 answer:
Levart [38]3 years ago
5 0

Answer:

Because the Earth has so much gravity, it can hold water, land, and life in it's atmosphere.

(Not sure what beaker you are talking about, so sorry) But I don't think the moon's gravity would have an effect on a beaker of water because the Earth's gravity is much more than the moon's.

I think you would be able to feel a little bit of Earth's gravity  on the moon because the Earth's gravity pulled the moon into orbit, therefore, gravity on Earth my have some effect on the moon.

hope this helps!

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Describe a situation where an object has a change in velocity but constant speed
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-- the little ball going round and round a spinning roulette wheel

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-- any Earth satellite in a perfectly circular orbit.
The closest thing to it is a geostationary TV satellite ... they try hard
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8 0
3 years ago
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A prediction or educated guess that can be tested is ?
Ksivusya [100]
An educated guess is a “hypothesis”
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3 years ago
A standing wave measures 12 m between its first and fourth node and its frequency 325 Hz. What is the standing wave's speed?
satela [25.4K]

Answer:

1300 m/s

Explanation:

Applying,

v = λf/2............... Equation 1

Where v = velocity or speed of wave, f = frequency of wave, λ = wavelength of wave.

From the question,

Given: f = 325 Hz, λ = (12×2/3) = 8 m

Substitute these values into equation 2

v = 325(8)/2

v = 1300 m/s.

Hence the standing wave speed is 1300 m/s

The right option is 1300 m/s

8 0
3 years ago
A strip of copper 150 μm thickand 4.5 mm wide is placed in a uniform magnetic field B (vector) ofmagnitude 0.65 T, with B (vecto
kykrilka [37]

Answer:

V_H=7.3544\times 10^{-6} \,V

Explanation:

Given that:

thickness of the metal strip, d=150\times 10^{-6} m

width of the metal strip, w=4.5\times 10^{-3}m

magnitude of the perpendicular magnetic field, B=0.65 \,T

current through the strip, I=23\,A

charge density, n=8.47\times 10^{28} \,electrons\,per\,m^3

Hall voltage is a transverse voltage given by:

V_H=\frac{I.B}{n.e.d}

putting the respective values

V_H=\frac{23\times 0.65}{(8.47\times 10^{28})\times 1.6\times 10^{-19}\times (150\times 10^{-6} )}

V_H=7.3544\times 10^{-6} \,V

Note:

V = E d is used when a charge is moved in a uniform electric field between the two oppositely charged plates, it can't be used here because it is the case of Hall effect where the small voltage develops transverse  to the direction of current flow.

6 0
3 years ago
Help with 26 please:):)
Alik [6]
$0.080 per kWh

25W porch light

a day = 24hrs

365 days in a year = 8760hrs


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0.025kW in the porch light



2) kW in a year

0.025kW × 8760hrs = 219 kWh in a whole year



3) money

$0.080 × 219kWh = $17.52







8 0
3 years ago
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