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zhuklara [117]
2 years ago
12

What is one key physical difference between transition metals and poor metals?

Physics
1 answer:
adoni [48]2 years ago
5 0

Answer:

HARDNESS

Explanation:

One key physical difference between transition metals and poor metals is their "" Hardness"" which is

the ability of a material to resist deformation. The test for hardness can be determined by a standard test which is the measurement of surface resistance to indentation. hardness tests are defined the shape and also type of indent.

The poor metals are also referred to as post transition metals. They are elements that are found at the right of the transition metals,they are located in the p-block,Their properties is as a result of their low melting and boiling point compare to other metals.They have high electronegativity and conductivity but softer texture compare to other metals.They are very soft more than the transition metals, but they cannot be cannot be classified as metalloids.

Poor metals includes elements in the periodic table such as; aluminium, gallium, indium, thallium, tin, lead, bismuth, and polonium.

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Answer:

Different

Explanation:

The hollow one will expand even more making it have a larger volume then the solid one so they are different

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Hull (1943) had rats push a lever that required 21 grams of force to budge. After they had learned to push the lever in order to
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1 year ago
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A rock is thrown down from the top of a cliff with a velocity of 3.61 m/s (down). The cliff is 28.4 m above the ground. Determin
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a shell fired from a cannon at 60 ° from horizontal strikes a target 20m high at a distance 80m. Calculate the initial velocity
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consider the motion along the X-direction

X = horizontal displacement = 80 m

V_{ox} = initial velocity along the x-direction = v Cos60

t = time of travel

using the equation

X = V_{ox}   t

80 = (v Cos60) (t)

t = 160/v                                         eq-1


consider the motion in vertical direction :

Y = vertical displacement = 20 m

V_{oy}  = initial velocity in Y-direction = v Sin60

a = acceleration = - 9.8 m/s²

t = time of travel = 160/v

using the equation

Y = V_{oy}  t + (0.5) a t²

20 = (v Sin60) (160/v) + (0.5) (- 9.8) (160/v)²

v = 32.5 m/s

4 0
3 years ago
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