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3 years ago

A nickel is placed in a cup of boiling water. Predict whether a solution will form.

Chemistry

1 answer:

Volgvan3 years ago

6 0

I think the copper could melt to cup and the water would smell like rust

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What is the [H+] concentration of blood, given the ph is 2.5?

belka [17]

Answer:

0.00316

Explanation:

You have to use the following equation:

$pH=-log[H^+]$

You are given the pH and need to find the concentration of H+. Plug in the given components and solve.

$2.5=-log[H^+]\\H^+ = 10^{-2.5}\\H^+=0.00316$

The concentration of H is 0.00316.

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3 years ago

Help me pleaseee I need it!

sashaice [31]

They have the most moons because they have the most mass

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2 years ago

Private land is generally used for _______. a. homes b. businesses c. factories d. all of the above Please select the best answe

alekssr [168]

HM, I think the answer would be D. This is just a guess, so please use it if ou want to answer D it's ok :D

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3 years ago

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Which three groups of the periodic table contain the most elements classified as metalloids (semimetals)?

attashe74 [19]

The metalloids are mostly concentrated in groups 14, 15, and 16. (Some simpler charts will show them as 4A, 5A, and 6A - take a look at the top of the periodic table your class uses to double-check).

If you like my answer, please vote me a 'brainliest' - trying to improve my rank :-)

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4 years ago

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Calculate the hight of a column of liquid glycerol in meters required to exert the same pressure as 3.02 m if CCl4?

katovenus [111]

Answer:

Approximately $3.81\; \rm m$ .

Explanation:

Look up the density $\rho$ of carbon tetrachloride, $\rm CCl_4$ , and glycerol:

Density of carbon tetrachloride: approximately $1.59\times 10^{3}\; \rm kg \cdot m^{-3}$ .
Density of glycerol: approximately $1.26\times 10^{3}\; \rm kg \cdot m^{-3}$ .

Let $g$ denote the gravitational field strength. (Typically $g \approx 9.81\; \rm N \cdot kg^{-1}$ near the surface of the earth.) For a column of liquid with a height of $h$ , if the density of the liquid is $\rho$ , the pressure at the bottom of the column would be:

$P = \rho\cdot g \cdot h$ .

The pressure at the bottom of this carbon tetrachloride column would be:

$\begin{aligned} P &= \rho \cdot g \cdot h \\ & \approx 1.59\times 10^{3} \; \rm kg \cdot m^{-3} \times 9.81\; \rm N \cdot kg^{-1} \times 3.02 \; \rm m \approx 4.71 \times 10^{4} \; \rm N \cdot m^{-2} \end{aligned}$ .

Rearrange the equation $P = \rho\cdot g \cdot h$ for $h$ :

$\displaystyle h = \frac{P}{\rho \cdot g}$ .

Apply this equation to calculate the height of the liquid glycerol column:

$\begin{aligned}h &= \frac{P}{\rho \cdot g} \\ &\approx \frac{4.71 \times 10^{4}\; \rm N \cdot m^{-2}}{1.26 \times 10^{3}\; \rm kg \cdot m^{-3} \times 9.81\; \rm N \cdot kg^{-1}} \approx 3.81\; \rm m\end{aligned}$ .

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3 years ago