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3 years ago

In the reaction: ch3cooh(aq) + nh2â(aq) ch3cooâ(aq) + nh3(aq), the conjugate acid-base pairs are:

Chemistry

1 answer:

Arlecino [84]3 years ago

3 0

CH₃COOH-CH₃COO⁻ is a conjugate acid-base pair. NH₃-NH₂⁻ is another conjugate acid-base pair

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What is callibration of temperature

Mademuasel [1]

ouch that hurts

What is Temperature Calibration? Temperature calibration refers to the calibration of any device used in a system that measures temperature. Most importantly, this usually means the temperature sensor, itself, which is typically a platinum resistance thermometer (PRT or PT-100), thermistor, or thermocouple.

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3 years ago

SOMEONE PLEASE HELP

Snowcat [4.5K]

Answer:

a. release of heat flames or light - Physical Change

b. formation of precipitate - Chemical Change

c. change in substances size - Physical Change

d. change in an objects shape - Physical Change

e. change in an objects phase of matter - Physical Change

f. releasing gases/bubbles - Chemical Change

Explanation:

These are all either changes in physicality or in chemical structures; hope I helped either way!

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3 years ago

Substance ΔG°f(kJ/mol) M3O4(s) −8.80 M(s) 0 O2(g) 0 Consider the decomposition of a metal oxide to its elements, where M represe

baherus [9]

Answer:

The equilibrium constant is $K =0.02867$

The equilibrium pressure for oxygen gas is $P_{O_2} = 0.09367\ atm$

Explanation:

From the question we are told that

The equation of the chemical reaction is

$M_2 O_3 _{(s)} ----> 2M_{(s)} + \frac{3}{2} O_2_{(g)}$

The Gibbs free energy for $M_3 O_4_{(s)}$ is $\Delta G^o_{1} = -8.80 \ kJ/mol$

The Gibbs free energy for $M{(s)}$ is $\Delta G^o_{2} = 0 \ kJ/mol$

The Gibbs free energy for $O_2{(s)}$ is $\Delta G^o_{3} = 0 \ kJ/mol$

The Gibbs free energy of the reaction is mathematically represented as

$\Delta G^o_{re} = \sum \Delta G^o _p - \sum G^o _r$

$\Delta G^o_{re} = \sum \Delta G^o _1 - \sum( G^o _2 +G^o _3)$

Substituting values

From the balanced equation

$\Delta G^o_{re} =[ (2 * 0) + (\frac{3}{2} * 0 )] - [1 * - 8.80]$

$\Delta G^o_{re} = 8.80 kJ/mol =8800J/mol$

The Gibbs free energy of the reaction can also be represented mathematically as

$\Delta G^o_{re} = -RTln K$

Where R is the gas constant with a value of $R = 8.314 J/mol \cdot K$

T is the temperature with a given value of $T = 298 K$

K is the equilibrium constant

Now equilibrium constant for a reaction that contain gas is usually expressed in term of the partial pressure of the reactant and products that a gaseous in state

The equilibrium constant for this chemical reaction is mathematically represented as

$K_p =[ P_{O_2}]^{\frac{3}{2} }$