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Lunna [17]
3 years ago
12

100 POINTS AND BRAINLIEST! What were the Magdeburg Hemispheres?

Physics
2 answers:
amm18123 years ago
8 0

The Magdeburg hemispheres are a pair of large copper hemispheres, with mating rims. They were used to demonstrate the power of atmospheric pressure. When the rims were sealed with grease and the air was pumped out, the sphere contained a vacuum and could not be pulled apart by teams of horses.

pogonyaev3 years ago
7 0

Answer:

Magdeburg hemispheres are two half-spheres of equal size. Placing them together traps air between them. This air is merely trapped, and not compressed, so the pressure inside is the same as the pressure of the atmosphere outside the spheres. The spheres thus pull apart with nearly no resistance.

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An observer notes that the pitch of a sound is becoming progressively higher.the observer can conclude that the sound is moving
Dahasolnce [82]
The observer can conclude that the sound is moving away from them and that its speed is increasing.
6 0
3 years ago
It takes 3 minutes to make toast in a 1500 watt toaster. Calculate how much work is done by the toaster.
REY [17]

Answer: 2.7 x 10^5 joules

Explanation:

Given that:

Time taken = 3 minutes

convert time in minutes to seconds

(Since 1 minute = 60 seconds

3 minutes = 3 x 60 = 180 seconds)

Power of toaster = 1500 watt

Work done by the toaster = ?

Recall that power is the rate of work done per unit time

i.e Power = work/time

work = Power x Time

Work = 1500 watt x 180 seconds

Work = 270000J

Place the result in standard form

270000J = 2.7 x 10^5J

Thus, 2.7 x 10^5 joules of work is done by the toaster.

3 0
3 years ago
The work done in holding a 30kg of bricks to a height of 20m is
ella [17]
The work done to "HOLD" a load of bricks at any height is zero.
Work is done only when force acts through a DISTANCE.

The work done to LIFT 30 kg of anything to 20m higher than
it already is, is

(force) · (vertical distance)

= (mass) · (gravity) · (vertical distance)

= (30 kg) · (9.8 m/s²) · (20 m)

= 5,880 joules
8 0
3 years ago
How much work does a student (m = 60 kg) do when he Climb a tower 80 m high?
gtnhenbr [62]

Answer:

W = 47040  J

Explanation:

Given that,

The mass of a student, m = 60 kg

Height of the tower, h = 80 m

We need to find the work done in climbing the tower. The work done is given by :

W = mgh

So,

W = 60 × 9.8 × 80

W = 47040  J

So, the required work done is 47040  J.

7 0
3 years ago
A 1000-kg car traveling north at 15 m/s collides with a2000-kg truck traveling east at 10 m/s. The occupants, wearing seat belts
Aleksandr-060686 [28]

Answer:

8.33 m/s, 36.87° North of East

Explanation:

m_n = Mass of car = 1000 kg

v_n = Velocity of car = 15 m/s

m_e = Mass of truck = 2000 kg

v_e = Velocity of truck = 10 m/s

M = Combined mass = 1000+2000 = 3000 kg

Momentum

p_n=m_nv_n\\\Rightarrow p_n=1000\times 15\\\Rightarrow p_n=15000\ kgm/s

Momentum of car traveling East is 15000 kgm/s

p_e=m_ev_e\\\Rightarrow p_n=2000\times 10\\\Rightarrow p_n=20000\ kgm/s

Momentum of truck traveling North is 20000 kgm/s

Angle

\theta=tan^{-1}\frac{p_n}{p_e}\\\Rightarrow \theta=tan^{-1}\frac{15000}{20000}\\\Rightarrow \theta=36.87^{\circ}

As the two vehicles are vectors, the resultant velocity is

(Mv)^2=p_n^2+p_e^2\\\Rightarrow v=\sqrt{\frac{p_n^2+p_e^2}{M^2}}\\\Rightarrow v=\sqrt{\frac{15000^2+20000^2}{3000^2}}\\\Rightarrow v=8.33\ m/s

Velocity of the two vehicles when they are locked together is 8.33 m/s and direction is 36.87° North of East

5 0
3 years ago
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