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Lunna [17]
3 years ago
12

100 POINTS AND BRAINLIEST! What were the Magdeburg Hemispheres?

Physics
2 answers:
amm18123 years ago
8 0

The Magdeburg hemispheres are a pair of large copper hemispheres, with mating rims. They were used to demonstrate the power of atmospheric pressure. When the rims were sealed with grease and the air was pumped out, the sphere contained a vacuum and could not be pulled apart by teams of horses.

pogonyaev3 years ago
7 0

Answer:

Magdeburg hemispheres are two half-spheres of equal size. Placing them together traps air between them. This air is merely trapped, and not compressed, so the pressure inside is the same as the pressure of the atmosphere outside the spheres. The spheres thus pull apart with nearly no resistance.

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Which equations are equivalent to 3/4+m=-7/4? Select three options.
Karo-lina-s [1.5K]

Answer:

M= -10/4

M = -5/2

-5/4 + m = -15/4

Explanation:

3/4 + m = -7/4

Subtract 3/4 from both sides

3/4 + m - 3/4 = -7/4 - 3/4

m = (-7-3) / 4

m = -10/4

m = -5/2

Check the options

11/4 + m = -1/4

m = -1/4 - 11/4

m = (-1-11) /4

m = -12/4

m = -3

-5/4 + m = -15/4

m = -15/4 + 5/4

m = (-15+5) /4

m = -10/4

m = -5/2

5 0
3 years ago
What is the difference between these two kinds of seismic waves: body waves and surface waves?
Ahat [919]
<span>A body wave is a seismic wave that moves through the interior of the earth, as opposed to surface waves that travel near the earth's surface.

 P and S waves are body waves. Each type of wave shakes the ground in different ways</span>
4 0
3 years ago
I need to speak with zuka
Alex787 [66]

Answer:

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3 0
3 years ago
How does electric circuit wor
zaharov [31]
Electricity passes through it
4 0
4 years ago
A meter stick moves parallel to its axis with speed of 0.96 c relative to you. What would you measure for the length of the stic
Fed [463]

Answer:

The length of the stick is 0.28 m.

The time the stick take to move is 0.97 ns.

Explanation:

Given that,

Relative speed of stick v= 0.96 c

Speed of light c= 2.99793\times10^{8}\ m/s

Proper length of stick = 1 m

We need to calculate the length of the stick

Using formula of length

\Delta l=\Delta l_{0}\sqrt{(1-\dfrac{v^2}{c^2})}

Put the value into the formula

\Delta l=1\sqrt{1-\dfrac{(0.96)^2c^2}{c^2}}

\Delta l=1\sqrt{1-(0.96)^2}

\Delta l=0.28\ m

We need to calculate the time the stick take to move

Using formula of time

t=\dfrac{\Delta l}{v}

Put the value into the formula

t=\dfrac{0.28}{0.96\times(2.99793\times10^{8})}

t=9.72\times10^{-10}\ sec

t=0.97\ ns

Hence, The length of the stick is 0.28 m.

The time the stick take to move is 0.97 ns.

7 0
3 years ago
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