A gas with a vapor density greater than that of air, would be most effectively displaced out off a vessel by ventilation.
The two following principles determine the type of ventilation: Considering the impact of the contaminant's vapour density and either positive or negative pressure is applied.
Consider a vertical tank that is filled with methane gas. Methane would leak out if we opened the top hatch since its vapour density is far lower than that of air. A second opening could be built at the bottom to greatly increase the process' efficiency.
A faster atmospheric turnover would follow from air being pulled in via the bottom while the methane was vented out the top. The rate of natural ventilation will increase with the difference in vapour density. Numerous gases that require ventilation are either present in fairly low concentrations or have vapor densities close to one.
Answer:
The element is Aluminium. (assuming that the given quantum number set is for the valence electron of the unknown element)
Explanation:
The given quantum numbers are:
n=3 (Principal Quantum Number)
l=1 (Azimuthal Quantum Number)
m=0 (Magnetic Quantum Number)
s= -1/2 (Spin Quantum Number)
The given set of quantum numbers refer to the 3p orbital.
Assuming that this the valence electron of the element, the unkown element is Aluminium.
Answer:
1. 1.80x10⁻⁵ (w/w %).
2. 1.80x10⁻⁴ parts per thousand
3. 0.18 parts per million
Explanation:
The solution contains 45.1μg / 250mL.
1. Weight percent (100 times mass in grams of solute per gram of solution, as there are 250mL of water = 250g):
45.1x10⁻⁶g / 250g * 100 =
<h3>1.80x10⁻⁵ (w/w %)</h3>
2. Parts per thousand (mg of solute per g of solution).
45.1μg * (1x10⁻³mg / 1μg) = 0.0451mg.
0.0451mg / 250g =
<h3>1.80x10⁻⁴ parts per thousand</h3>
3. Parts per million (μg of solute per g of solution):
45.1μg / 250g =
<h3>0.18 parts per million</h3>
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