1. A ball is launched horizontally at 40 m/s while 6.0 m above a level field . How far will the ball move horizontally before st
1 answer:
Answer:
44 m
Explanation:
Given that,
Horizontal velocity of the ball, u = 40 m/s
It is 6 m above the level field.
We need to find the distance covered by the ball when move horizontally before striking the ground. Let it is d.
Firstly, we will find time taken for the ball to hit the ground. Using second equation of motion as follows :
Put u = 0 and a = g
No finding the horizontal distance as follows :
d = ut
d = 40 m/s × 1.1 s
d = 44 m
So, the ball will move 44 m horizontally before striking the ground.
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Answer:
a. μ 3 ± 1.8 = [1.2,4.8]
b. The correct answer is option D. No, because the sample size is large enough.
Explanation:
a. The population mean can be determined using a confidence interval which is made up of a point estimate from a given sample and the calculation error margin. Thus:
μ±(t*s)/sqrt(n)
where:
μ = is the 95% confidence interval estimate
x_ = mean of the sample = 3
s = standard deviation of the sample = 5.8
n = size of the sample = 41
t = the t statistic for 95% confidence and 40 (n-1) degrees of freedom = 2.021
substituting all the variable, we have:
μ 3 ± (2.021*5.8)/sqrt(41) = 3 ± 1.8 = [1.2,4.8]
b. The correct answer is option D. No, because the sample size is large enough.
Using the the Central Limit Theorem which states that regardless of the distribution shape of the underlying population, a sampling distribution of size which is ≥ 30 is normally distributed.