Answer: longhand notation
Explanation: I just did it on Edg
Answer is: formula of the complex is [Cr(NH₃)₂(SCN)₄<span>]</span>⁻<span>.
This complex has negative charge (-1) because chromium (central atom or metal) has oxidation number +3, first ligand ammonia has neutral charge and second ligand thiocyanate has negative oxidation number -1:
+3 + 2</span>·0 + 4·(-1) = -1.
The balanced equation for the reaction is as follows
2RbNO₃ --> 2RbNO₂ + O₂
stoichiometry of RbNO₃ to O₂ is 2:1
number of moles of RbNO₃ decomposed - 5.0 mol
when 2 mol of RbNO₃ decomposes, 1 mol of O₂ is formed
therefore when 5.0 mol of RbNO₃ decomposes - 5.0 / 2 = 2.5 mol of O₂
2.5 mol of O₂ is formed
Answer:
It gets squeeze together so tightly that four hydrogen nuclei combine to form one helium atom.
Explanation:
Answer: ΔH°f of gaseous nitrogen monoxide is 148.0 kJ/mol
Explanation:
The balanced chemical reaction is,
The expression for enthalpy change is,
where,
n = number of moles
(as heat of formation of substances in their standard state is zero
Now put all the given values in this expression, we get
Therefore, ΔH°f of gaseous nitrogen monoxide is 148.0 kJ/mol