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oksian1 [2.3K]
2 years ago
12

How does a catalyst increase the rate of a reaction?

Chemistry
1 answer:
sukhopar [10]2 years ago
6 0

Answer:

It increases the reaction rate by lowering the activation energy  for a reaction.

Please see the picture below in order to easier to understand.

Explanation:

However, note that there are positive and negative catalyst. The question above is just about the positive catalyst.

..

Hope this answer can help you.

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11cm+11.38cm+500.55cm=
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Answer:522.93 centimeters

Explanation:

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The graphic shows two isomers of a chemical compound with molecular formula C5H11NO2. Which type of isomers are these? A. struct
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When 50,0 g of silicon dioxide is heated with an excess of carbon, 32.2 g of
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The equilibrium constant, Kc, for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) Calculate the equilibri
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<u>Answer:</u> The equilibrium concentration of HCl is 2.26\times 10^{-3}M

<u>Explanation:</u>

We are given:

Moles of NH_4Cl(s) = 0.564 moles

Volume of vessel = 1.00 L

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}

Molarity of NH_4Cl=\frac{0.564}{1}=0.564M

The given chemical equation follows:

                  NH_4Cl(s)\rightleftharpoons NH_3(g)+HCl(g)

<u>Initial:</u>         0.564

<u>At eqllm:</u>     0.564-x          x              x

The expression of K_c for above equation follows:

K_c=[NH_3][HCl]

The concentration of pure solid and pure liquid is taken as 1.

We are given:

K_c=5.10\times 10^{-6}

Putting values in above equation, we get:

5.10\times 10^{-6}=x\times x\\\\x=2.26\times 10^{-3}M,-2.26\times 10^{-3}M

Negative sign is neglected because concentration cannot be negative.

So, [HCl]=2.26\times 10^{-3}M

Hence, the equilibrium concentration of HCl is 2.26\times 10^{-3}M

5 0
3 years ago
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