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viva [34]
3 years ago
12

Would someone just answer this?

Physics
1 answer:
Alecsey [184]3 years ago
8 0

Answer:

I answered :)

Explanation:

i just dk the right answer

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As the concentration of a solute in a solution increases, the freezing point of the solution ________ and the vapor pressure of
kykrilka [37]

Answer:

As the concentration of a solute in a solution increases, the freezing point of the solution <u><em>decrease </em></u>and the vapor pressure of the solution <em><u>decrease </u></em>.

Explanation:

Depression in freezing point :

\Delta T_f=K_f\times m

where,

\Delta T_f =depression in freezing point =  

K_f = freezing point constant  

m = molality  ( moles per kg of solvent) of the solution

As we can see that from the formula that higher the molality of the solution is directly proportionate to the depression in freezing point which means that:

  1. If molality of the solution in high the depression in freezing point of the solution will be more.
  2. If molality of the solution in low the depression in freezing point of teh solution will be lower .

Relative lowering in vapor pressure of the solution is given by :

\frac{p_o-p_s}{p_o}=\chi_{solute}

p_o = Vapor pressure of pure solvent

p_s  = Vapor pressure of solution

\chi_{solute} = Mole fraction of solute

p_s\propto \frac{1}{\chi_{solute}}

Vapor pressure of the solution is inversely proportional to the mole fraction of solute.

  1. Higher the concentration of solute more will the be solute's mole fraction and decrease in vapor pressure of the solution will be observed.
  2. lower the concentration of solute more will the be solute's mole fraction and increase in vapor pressure of the solution will be observed.
8 0
3 years ago
I don’t understand this please help.
ruslelena [56]
I couldnt type it out so here's a picture
3 0
3 years ago
Please help me guys please​
leonid [27]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Solution is in attachment ~

I hope that you got what you were looking for, and if there's different data then go through the same procedure, using same formula with different values and you will get your answer ~

\mathrm{✌TeeNForeveR✌}

8 0
2 years ago
if a boat was moving at a velocity of 30 m/s to the south and it sailed for 30 minutes, what was the displacement of the boat?
kifflom [539]

If you move south at 30 m/s for 30 minutes, your displacement is

D = (30 mtr/s) x (30 min) x (60 sec/min)

D = (30 x 30 x 60) (mtr-min-sec/sec-min)

D =  54,000 meters south

D = <em>54 km south</em>

8 0
3 years ago
Deceleration ALWAYS means slowing down while negative acceleration does not always have to be slowing down
alexgriva [62]
A little confused by the wording of the problem, but it is true that an object can have a negative acceleration and be speeding up in the negative direction… so I’d go with True
4 0
3 years ago
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