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tangare [24]
3 years ago
14

A particle accelerator fires a proton into a region with a magnetic field that points in the x-direction. (a) If the proton is m

oving in the y-direction, what is the direction of the magnetic force on the proton
Physics
1 answer:
iVinArrow [24]3 years ago
7 0

Answer:

<em>The magnitude of the magnetic field will act in a direction towards me.</em>

<em></em>

Explanation:

When a charged particle enters a magnetic field, it is deflected. The direction of travel of the particle is deflected, but the kinetic energy of the particle is not affected. <em>The force experienced by a charged particle as it enters a magnetic field that acts perpendicular to the path of the velocity of the particle, will produce a force that is perpendicular to both the direction of travel of the particle and the direction of the magnetic field.</em> In this case, the proton moves in the y-direction, the magnetic field is in the x-direction, therefore the force experienced by the particle will be towards me.

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<h2>Answer::</h2>

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I'm guessing that you mean like this:
-- The ruler is held with zero at the bottom, and the centimeter markings
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Then, all we have to find is the time it takes for the ruler to fall 11.3 cm .

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                              11.2 cm  =  (1/2) (9.8 m/s²) (time)²
or
                         0.112 meter  =  (4.9 m/s²) (time)²                      

Divide each side
by  4.9 m/s² :        (0.112 m) / (4.9 m/s²)  =  time²

                            (0.112 / 4.9)  sec²  =  time²

Square root
each side:            time = √(0.112/4.9  sec²)

                                  =  √ 0.5488 sec²

                                  =      0.74 second     (rounded)  

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