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vfiekz [6]
3 years ago
14

Consider an NACA 2412 airfoil with a 2-m chord in an airstream with a velocity of 50 m/s at standard sea level conditions. If th

e lift per unit span is 1353 N/m, what is the angle of attac
Physics
1 answer:
Akimi4 [234]3 years ago
8 0

Answer:

4°

Explanation:

Given,

chord in the airstream, c = 2 m

speed, v = 50 m/s

lift per unit span = 1353 N/m

density of air, ρ = 1.225 kg/m³

Lift,L = c_L \times \dfrac{1}{2} \rho v^2(c \times s)

\dfrac{L}{s}=c_L \times \dfrac{1}{2} \rho v^2\times c

50=c_L \times 0.5\times 1.225\times 50^2\times 2

c_L = 0.44

From the plot of c_L and angle of attack

Angle of attack is equal to 4°

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  • Force=150N
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So, substituting the values of the variables into E, we have

E = mgh + 1/2mv²

= 2.00 kg × 9.8 m/s² × 20.0 m + 1/2 × 2.00 kg × (20.0 m/s)²

=  392 J + 400 J

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2 years ago
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La clave para resolver este problema es mediante caída libre, la velocidad inicial del objeto es 0 por lo que podemos calcular la altura h de la casa mediante la relación h= \frac{gt^{2}}{2}.

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Answer:

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