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Nutka1998 [239]
3 years ago
13

A stone tied to a string is made to revolve in a

Physics
1 answer:
tia_tia [17]3 years ago
3 0

Answer:

<em>The tangential velocity is 8 m/s</em>

Explanation:

<u>Uniform Circular Motion</u>

It can be described as the motion of an object in a circle at a constant speed.

As an object moves in a circle, it continually changes its direction.

If the radius of the circle is r and the angular speed is w, then the tangential velocity is:

v = w.r

The stone is revolving in a circle of radius r=4 m with an angular speed of w=2 rad/s. The tangential velocity is:

v = 2 rad/s * 4 m

v = 8 m/s

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The magnetic field a distance 2 cm from a long straight current-carrying wire is 2 × 10–5 t. the current in the wire is:
Sliva [168]

Current in the wire = 2 A

Explanation:

the magnetic field is given by

B= \frac{\mu i}{2\pi r}

μo= 4π x 10⁻⁷ Tm/A

i= current

r=0.02 m

B = magnetic field= 2 x 10⁻⁵ T

2 x 10⁻⁵= (4π x 10⁻⁷)(i) / (2π*0.02)

i=2 A

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3 years ago
Lab: Energy Transfer Instructions Click the links to open the resources below. These resources will help you complete the assign
svetoff [14.1K]

Answer:

Give me a 5 star

Explanation:

Because im cool

6 0
3 years ago
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What is approximate resistance between P and Q?<br> a) 0.5<br> b)0.8<br> c)2.0<br> d)2.2<br> e)3.6
Rufina [12.5K]

Answer:

0.5 Ohms

Explanation:

We note that the node Q is also between the resistors of 1ohm and 2ohms.

We note that the node P is also between the resistors of 2ohms and 3ohms.

Thus, all these resistors are in parallel, beween nodes P and Q

1/Re=1/R1+1/R2+1/R3

1/Re=1/1+1/2+1/3=(6+3+2)/6=11/6 [ohm^(-1)]

Re=6/11=0.54ohms

Rounding to the tenth: Re=0.5 ohms

8 0
3 years ago
HELP ME!!! NO LINKS!!! Compare and Contrast the scientific definitions of theory and law. Explain why the first law of thermodyn
Nataly_w [17]
The date the model was published.

The use of “laws” originated prior to science splitting from natural philosophy. There’s an implicit assumption that God as the creator laid down both moral and natural laws, with the theologian concerned with the former and the natural philosopher concerned with the latter.

“Theory” begins to take hold in the late 1700s and, very roughly speaking, is used to describe more complex models. “Law” eventually became nearly archaic, although still used to describe very pithy models (Amdahl’s Law, Gustafson’s Law).

The word “model” is gradually superseding both of them.

People have tried to come up with hard-and-fast rules to distinguish them, but scientists are unruly beasts, and use whatever language suits them in the moment.
3 0
2 years ago
A 1500 kg truck traveling at 80 km/h collides with another car of mass 1000 kg traveling at 30 km/h in the same direction. The t
Likurg_2 [28]

Answer:

Their speed immediately after the collision is 60 km/h

Explanation:

The magnitude that characterizes the state of motion of a body is called the quantity of motion. The momentum of a particle of mass m moving with velocity v is defined as the product of mass and velocity:

p=m*v

Newton's second law states that to accelerate an object you must apply a force to it. In other words, to change the moment of an object, an impulse must be applied to it, an impulse that is produced by a force. In both cases there is an external agent that exerts the force or the impulse, the internal forces are not considered. When the force  net is zero, so the net momentum is zero, and therefore there is no change in total momentum. Then it can be stated that if a net force is not exerted on a system, the total moment of the system cannot change.

In summary, the principle of conservation of linear momentum, also known as the principle of conservation of momentum, states that if the resultant of the forces acting on a body or system is zero, its momentum remains constant in time.

Then before collision, the momentum of truck is  1,500 kg*80 km/h = 120,000 kg.km/h  and the momentum of car is  1,000 kg* 30 km/h = 30,000 kg.km/h

So, the total momentum before collision is  120,000 kg*km/h+ 30,000 kg*km/h = 150,000 kg.km/h

The two cars stick together after the collision. This means that the speed V of both is the same. Therefore, the momentum after collision is  

V*(1,500 kg + 1,000 kg)  = V*2,500 kg

Applying the law of conservation of momentum, that it states that the total momentum of two objects before collision is equal to the total momentum of the two objects after collision., you get:

150,000 kg.km/h= V*2,500 kg

Solving:

V=\frac{ 150,000 kg.km/h}{2,500 kg}

V= 60 km/h

<u><em>Their speed immediately after the collision is 60 km/h</em></u>

7 0
3 years ago
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