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Papessa [141]
2 years ago
7

How many chlorine atoms are on the products side of the reaction 2al 6hcl → 2alcl3 3h2? 2

Chemistry
2 answers:
baherus [9]2 years ago
7 0

Answer:

C. 6

Edg2021

Explanation:

Person is right.

MaRussiya [10]2 years ago
6 0

Answer:

6

Explanation:

The given reaction is aluminium with hydrochloric acid

2Al + 6HCl → 2AlCl3 + 3H2

the product is aluminium chloride and hydrogen gas.

We can clearly, calculate that there are 2*3=6 chlorine atoms in product side of the reaction.

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3 years ago
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2 years ago
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4 0
3 years ago
The following reaction shows the products when sulfuric acid and aluminum hydroxide react.
Elden [556K]

The correct answer is approximately 11.73 grams of sulfuric acid.

The theoretical yield of water from Al(OH)3 is lower than that of H₂SO₄. As a consequence, Al(OH)3 is the limiting reactant, H₂SO₄ is in excess.

The balanced equation is:

2Al(OH)₃ + 3H₂SO₄ ⇒ Al₂(SO₄)₃ + 6H₂O

Each mole of Al(OH)3 corresponds to 3/2 moles of H₂SO₄. The molecular mass of Al(OH)3 is 78.003 g/mol. There are 15/78.003 = 0.19230 moles of Al(OH)3 in the five grams of Al(OH)3 available. Al(OH)3 is in limiting, which means that all 0.19230 moles will be consumed. Accordingly, 0.19230 × 3/2 = 0.28845 moles of H₂SO₄ will be consumed.

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6 0
3 years ago
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