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Answer: 4.21×10⁻⁸
Explanation:
1) Assume a general equation for the ionization of the weak acid:
Let HA be the weak acid, then the ionization equation is:
HA ⇄ H⁺ + A⁻
2) Then, the expression for the ionization constant is:
Ka = [H⁺][A⁻] / [HA]
There, [H⁺] = [A⁻], and [HA] = 0.150 M (data given)
3) So, you need to determine [H⁺] which you do from the pH.
By definition, pH = - log [H⁺]
And from the data given pH = 4.1
⇒ 4.10 = - log [H⁺] ⇒ [H⁺] = antilog (- 4.10) = 7.94×10⁻⁵
4) Now you have all the values to calculate the expression for Ka:
ka = 7.94×10⁻⁵ × 7.94×10⁻⁵ / 0.150 = 4.21×10⁻⁸
Answer:
23.0 s⁻¹ is rate constant
Explanation:
Using the Arrhenius equation:
k = A * e^(-Ea/RT)
Where k is rate constant
A is frequency factor (1.5x10¹¹s⁻¹)
Ea is activation energy = 55800J/mol
R is gas constant (8.314J/molK)
And T is absolute temperature (24°C + 273 = 297K)
Replacing:
k = 1.5x10¹¹s⁻¹ * e^(-55800J/mol/8.314J/molK*297K)
k = 1.5x10¹¹s⁻¹ * 1.53x10⁻¹⁰
k = 23.0 s⁻¹ is rate constant i hope this helpsss
Explanation:
Answer:
there are 3 significant figures
Explanation:
do not count the first 2 zeros. only the nimbers after the zero
The equilibrium constant is a value which represents the equilibrium of a reaction. It is a reaction quotient when the reaction reached equilibrium. If Keq is greater than 1, the mixture contains mostly the products. On the other hand, if Keq is less than 1, the mixture contains the reactants. For this case, the mixture contains mostly products.
