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GenaCL600 [577]

2 years ago

13

Determine the magnitude of the electrostatic force on a 0.06000 C charged object when it is placed in an electric field of magni

tude 1500 N/C

1 answer:

joja [24]2 years ago

3 0

Answer:

Explanation:

Use the following equation:

$E=\frac{q}{F}$ and solve for F:

$F=\frac{q}{E}$ and filling in:

$F=\frac{.0600}{1500}$

F = 4.0 × $10^{-4$ N

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With a mass of 109 kg, Baby Bird is the smallest monoplane ever

OLga [1]

Total resultant velocity=5.11-3.27=1.84m/s

m_1=61.4kg
m_2=109kg
v_1=1.84m/s
v_2=?

$\\ \sf\longmapsto ∆P=P$

$\\ \sf\longmapsto m_1v_1=m_2v_2$

$\\ \sf\longmapsto v_2=\dfrac{m_1v_1}{m_2}$

$\\ \sf\longmapsto v_2=\dfrac{61.4(1.84)}{109}$

$\\ \sf\longmapsto v_2=112.976/109$

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2 years ago

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Answer:

Explanation:

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2 years ago

What equation describes conservation of charge?

Phantasy [73]

Answer:

The equation which describes conservation of charge is $Q_{initial} - Q_{final } = 0$

Explanation:

The law of conservation charge states that for an isolated system that sum of initial charges is equal to sum of final charges, that is the total charge is conserved.

let the sum of initial charges = $Q_{initial}$

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2 years ago

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lys-0071 [83]

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5 0

2 years ago

a current of 5 ampere is passed for 2 hours in an electric iron having a resistance of 100 ohms calculate the heat produced

Alina [70]

Answer:

$\boxed{\sf Heat \ produced \ (H) = 5 \ kWh}$

Given:

Resistance (R) = 100 Ω

Current (I) = 5 A

Time (t) = 2 hours

To Find:

Heat developed (H) in the electric iron

Explanation:

Formula:

$\boxed{ \bold{ \sf H = I^2Rt}}$

Substituting values of I, R & t in the equation:

$\sf \implies H = {5}^{2} \times 100 \times 2 \\ \\ \sf \implies H = 25 \times 100 \times 2 \\ \\ \sf \implies H = 5000 \\ \\ \sf \implies H = 5 \: kWh$

$\therefore$

Heat developed (H) in the electric iron = 15 kWh

3 0

2 years ago