I think it would be oxygen
Enthalpy change is the term given to the concentration of the heat absorbed or evolved in a reaction carried out at a constant pressure. It is given by the symbol ΔH.
Enthalpy change = m (Cwater × dT + Hvap + Csteam × dT
dHvap = 40.67 kJ/mol = 40.67 × 103/18 = 2259.4 J/g
Enthalpy change = 5.00 [4.18 × (100-14) + 2259.4 + 1.84 × (115-100)]
= 13232.4 J
Answer:
Explanation:
Covalent bond:
It is formed by the sharing of electron pair between bonded atoms.
The atom with larger electronegativity attract the electron pair more towards itself and becomes partial negative while the other atom becomes partial positive.
Non polar covalent bond:
It is the bond where both bonded atoms share the pair of electron equally.
For example:
Hydrogen gas (H₂) is non polar covalent compound because the electronegativity of both bonded atoms are same. No poles are created that's why this is non polar covalent compound.
Polar covalent bond:
It is the bond where both bonded atoms share the pair of electron unequally.
For example:
In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive and bond is polar.
Im not sure but here is some information to help A declarative question is a yes-no question that has the form of a declarative sentence but is spoken with rising intonation at the end. Declarative sentences are commonly used in informal speech to express surprise or ask for verification.
Answer:
The three statements are true
Explanation:
For the reaction:
I₂O₅(s) + 5CO(g) → I₂(s) + 5CO₂(g)
State oxidation of iodine in I₂O₅ is:
5 O²⁻ = 10⁻
As you have 2 I and the molecule has no charge, <em>oxidation state of I is +5</em>.
The carbon in CO has an oxidation state of +2 and in CO₂ is +4. That means <em>the carbon is oxidized</em>
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An oxidizing agent is a substance that produce the oxidation of the agent that reacts with this one. CO is oxidized because of I₂O₅ is producing its oxidation being <em>the oxidizing agent</em>
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Thus,<em> the three statements are true</em>.
