The pH of 0.35 M of CH₃NH₂ is 12.09 and the
for methylamine is 4.4 x 10⁻⁴.
<h3>What is pH?</h3>
pHis the quantitative measure of acidity and basicity of an aqueous or other liquid solution. The scale range goes from 0 to 14. Water has a pH of 7 and is neutral in nature.
<h3>What is dissociation constant?</h3>
The dissociation constant is an equilibrium constant that describes the dissociation or ionization of a base or an acid
describes the dissociation of an acid
describes the dissociation of a base
For methylamine,

Initial concentration of methylamine = 0.35 M
Initial concentration of products = 0
Let, at equilibrium concentration of CH₃NH₂ = 0.35 - x
Then, concentration of CH₃NH₃⁺ and OH⁻ is x and x respectively
![k_b = \frac{[CH_3NH_3^+] [OH^-]}{[CH_3NH_2]}](https://tex.z-dn.net/?f=k_b%20%3D%20%5Cfrac%7B%5BCH_3NH_3%5E%2B%5D%20%5BOH%5E-%5D%7D%7B%5BCH_3NH_2%5D%7D)
The dissociation constant for methylamine,
= 4.4 x 10⁻⁴


pOH = -log[OH] = -log(0.0124) = 1.91
pH + pOH = 14
pH = 14 - 1.91 = 12.09
Thus, the pH of methylamine is 12.09 and
is 4.4 x 10⁻⁴
Learn more about pH:
brainly.com/question/172153
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