What is the equilibrium constant expression for the given system?
1 answer:
<h3>
Answer:</h3>
![\displaystyle K_{eq} = \frac{[H_2]^2[O_2]}{[H_2O]^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20K_%7Beq%7D%20%3D%20%5Cfrac%7B%5BH_2%5D%5E2%5BO_2%5D%7D%7B%5BH_2O%5D%5E2%7D)
<h3>
General Formulas and Concepts:</h3>
<u>Chemistry</u>
<u>Aqueous Solutions</u>
<u>Kinetics</u>
<u>Equilibrium</u>
- Equilibrium Reactions RxN ⇄
- Equilibrium Constants
- Equilibrium Expression:
![\displaystyle K = \frac{[Producst]^{coefficients}}{[Reactants]^{coefficients}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20K%20%3D%20%5Cfrac%7B%5BProducst%5D%5E%7Bcoefficients%7D%7D%7B%5BReactants%5D%5E%7Bcoefficients%7D%7D)
<h3>
Explanation:</h3>
*Note: Only gases and liquids affect equilibrium
<u>Step 1: Define</u>
[RxN - Balanced] 2H₂O (g) ⇄ 2H₂ (g) + O₂ (g)
<u>Step 2: Identify</u>
[Reactant] H₂O
[Product] H₂
[Product] O₂
<u>Step 3: Write K Expression</u>
- Substitute:
![\displaystyle K_{eq} = \frac{[H_2]^2[O_2]}{[H_2O]^2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20K_%7Beq%7D%20%3D%20%5Cfrac%7B%5BH_2%5D%5E2%5BO_2%5D%7D%7B%5BH_2O%5D%5E2%7D)
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I’m pretty sure the answer would be
24.6078
Hopefully that helps
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Atoms of sulfur = 9.60⋅g32.06⋅g⋅mol−1×6.022×1023⋅mol−1 . Because the units all cancel out, the answer is clearly a number, ≅2×1023 as required.
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Hope this helps :)