Answer:
it is true because there is west,south and etc
<span>Answer is: the mass of hydrogen is 22,05 grams.
m(</span>Al(C₂H₃O₂)₃)<span> = 500 g.
M</span>(Al(C₂H₃O₂)₃) = 27 + 6 ·12 + 9 · 1 + 6 · 16 · g/mol = 204 g/mol.<span>
n</span>(Al(C₂H₃O₂)₃) = m(Al(C₂H₃O₂)₃) ÷ M(Al(C₂H₃O₂)₃).
n(Al(C₂H₃O₂)₃) = 500 g ÷ 204 g/mol.
n(Al(C₂H₃O₂)₃) = 2,45 mol.
n(Al(C₂H₃O₂)₃) : n(H) = 1 : 9.
n(H) = 22,05 mol.
m(H) = 22,05 mol · 1 g/mol
m(H) = 22,05 g.
Given reaction:
N2(g) + 3H2(g) → 2NH3(g)
The standard free energy change is given as:
ΔG° = ∑ nΔGf(products) - ∑ nΔGf(reactants)
= [2ΔGf(NH3(g))] - [ΔGf(N2(g)) + 3ΔGf(H2(g))]
= [2(-16.48)] - [ 1(0) + 3(0)] = -32.96 kJ
Ans: Free energy of the reaction is -32.96 kJ, i.e. reaction is spontaneous.
Thewater of hydration x in narceine. xH₂O is 3
<h3>
What is Water of Hydration?</h3>
- In chemistry, water molecules found inside crystals are referred to as "water of crystallization" or "water of hydration." When crystals are formed from aqueous solutions, water is frequently included.
- The entire mass of water in a substance at a specific temperature is sometimes referred to as water of hydration, and it is typically present in a stoichiometric ratio.
- The term "water of crystallization" has historically been used to describe water that is not physically linked to the metal cation but is present in the crystalline structure of a metal complex or salt.
- Many chemicals include water molecules in their crystalline structures when they crystallize from water or solvents that contain water. Heating a sample usually removes the water of crystallization, but the crystalline qualities are frequently lost.
Given that hydrate is 10.8% by mass
molar mass = 499.52 g/mol
calculating the amount of water
mass of water = 
mass of water = 53.95 g
moles of water = 
moles of water =
= 3
then the water of hydration x in narceine. xH₂O is 3
To learn more about water of hydration with the given link brainly.com/question/4355575
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