Answer:
Final speed of boat + man is 1.66 m/s
Explanation:
As we know that there is no friction on the system or there is no external force on this system
So here we can use momentum conservation here
![mv = (m + M)v_f](https://tex.z-dn.net/?f=mv%20%3D%20%28m%20%2B%20M%29v_f)
so we have
m = 85 kg
M = 135 kg
v = 4.30 m/s
now we have
![85 \times 4.30 = (85 + 135) v](https://tex.z-dn.net/?f=85%20%5Ctimes%204.30%20%3D%20%2885%20%2B%20135%29%20v)
![v = 1.66 m/s](https://tex.z-dn.net/?f=v%20%3D%201.66%20m%2Fs)
Answer:
S = 2 π R
R (mean) = 92.9E6 miles
S = 2 * 3.14 * 92.9E6 miles = 5.84E8 miles
Answer:
The person is running at a speed of 2.564 m/s
Explanation:
Given;
mechanical energy dissipated per kilogram per step, E/kg/S = 0.6 J/kg/S
mass of the person, m = 52 kg
power developed by the person, P = 80 W
mechanical energy of the person per step, E = 0.6 J/kg x 52 kg
= 31.2 J
mechanical energy for the total step,
= 31.2 J x S
P = E / t
![P_{avg} = \frac{E_{total}}{t} \\\\P_{avg} = \frac{E_{step}*S}{t}\\\\\frac{P_{avg}}{E_{step}} = \frac{S}{t} \\\\\frac{S}{t} = \frac{80}{31.2} \\\\\frac{S}{t} = 2.564 \ m/s](https://tex.z-dn.net/?f=P_%7Bavg%7D%20%3D%20%5Cfrac%7BE_%7Btotal%7D%7D%7Bt%7D%20%5C%5C%5C%5CP_%7Bavg%7D%20%3D%20%5Cfrac%7BE_%7Bstep%7D%2AS%7D%7Bt%7D%5C%5C%5C%5C%5Cfrac%7BP_%7Bavg%7D%7D%7BE_%7Bstep%7D%7D%20%3D%20%5Cfrac%7BS%7D%7Bt%7D%20%5C%5C%5C%5C%5Cfrac%7BS%7D%7Bt%7D%20%3D%20%5Cfrac%7B80%7D%7B31.2%7D%20%5C%5C%5C%5C%5Cfrac%7BS%7D%7Bt%7D%20%3D%202.564%20%5C%20m%2Fs)
Therefore, the person is running at a speed of 2.564 m/s
The answer would be Newton’s Second Law
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