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cupoosta [38]
3 years ago
13

In the process of changing a flat tire, a motorist uses a hydraulic jack. She begins by applying a force of 58 N to the input pi

ston, which has a radius r1. As a result, the output plunger, which has a radius r2, applies a force to the car. The ratio r2/r1 has a value of 8.2. Ignore the height difference between the input piston and output plunger and determine the force that the output plunger applies to the car.
Physics
1 answer:
AfilCa [17]3 years ago
6 0

Answer:

The correct answer is "3899.92 N".

Explanation:

The given values are:

Force,

F_{app}=58 N

Ratio,

\frac{R_2}{R_1}=8.2

As we know,

Area, A=\pi r^2

or,

⇒  \frac{F_2}{F_1} =\frac{A_2}{A_1}

On substituting the value of "A", we get

⇒  \frac{F_2}{F_1} =\frac{\pi r_2^2}{\pi r_1^2}

⇒  \frac{F_2}{F_1} =\frac{r_2^2}{r_1^2}

On applying cross-multiplication, we get

⇒  F_2=F_1\times (\frac{r_2}{r_1} )^2

On substituting the given values, we get

⇒       =58\times (8.2)^2

⇒       =58\times 67.2

⇒       =3899.92 \ N

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You need to focus a 10 mW, 632.8 nm Gaussian laser beam that is 5.0 mm in diameter into a sample. You have access to a lens with
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Answer:

ee that the lens with the shortest focal length has a smaller object

           

Explanation:

For this exercise we use the constructor equation or Gaussian equation

        \frac{1}{f}  = \frac{1}{p} + \frac{1}{q}

where f is the focal length, p and q are the distance to the object and the image respectively.

Magnification a lens system is

          m = \frac{h'}{h} = - \frac{q}{p}

             h ’= -\frac{h q}{p}

In the exercise give the value of the height of the object h = 0.50cm and the position of the object p =∞

Let's calculate the distance to the image for each lens

f = 6.0 cm

           \frac{1}{q} = \frac{1}{f }  - \frac{1}{p}

as they indicate that the light fills the entire lens, this indicates that the object is at infinity, remember that the light of the laser rays is almost parallel, therefore p = inf

          q = f = 6.0 cm

for the lens of f = 12.0 cm q = 12.0 cn

to find the size of the image we use

           h ’= h q / p

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           h ’= h / p q

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3 years ago
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To Find :

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Now, fraction of initial kinetic energy loss is :

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