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sweet-ann [11.9K]
4 years ago
14

Question: Multicellular organisms have five levels of organization ranging from simplest to most complex. The simplest level is

the cellular level. This is an image of one type of cell found in your body: a cheek cell. You are the most complex level: you are an organism. List the five levels of organization, from simplest to most complex. Describe each level with one or two sentences. Give an example at each level.
Chemistry
2 answers:
lapo4ka [179]4 years ago
8 0
From Simplest to Most Complex, it follows this order.

Cells
Tissue
Organs
Organ Systems
Organisms

Given a sentence and an exmaple about them:

Cells: They are the fundamentals in all living things. They have a nucleus, cytoplasm, and organelles which is all surrounded by a cell membrane. Example: Skin Cells, Blood Cells.

Tissue: It is close to Cells, it consists of the material that animals and plants are made, but it also consists specialized cells and their product. Example: Muscle Tissue, Epithelial Tissue.

Organs: Pretty much a part of the body that specializes in a specific function. Example: Liver, Stomach.

Organ System: This is kind of like Organs, however they are a system of organs that rely on each other, whether it is directly or indirectly. Examples: Muscular System, Circulatory System.

Organelles: These are the parts that makes up what a cell is. Exmaple: Golgi Body, Lysosomes.
Norma-Jean [14]4 years ago
5 0

Answer:Multicellular organisms are made of many parts that are needed for survival. These parts are divided into levels of organization. There are five levels: cells, tissue, organs, organ systems, and organisms.

Explanation:

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The combustion of 3.795 mg of liquid B, which contains only C, H, and O, with excess oxygen gave 9.708 mg of CO2 and 3.969 mg of
attashe74 [19]

Answer:

Explanation:

9.708 mg of CO₂ will contain 12 x 9.708 / 44 = 2.64 g of C .

3.969 mg of H₂O will contain 2 x 3.969 / 18 = .441 g of H .

mg of O in given liquid B = 3.795 - ( 2.64 + .441 ) = .714 mg

ratio of mg of C , H , O in the compound = 2.64 : .441 : .714

ratio of no of atoms  of C , H , O in the compound

= 2.64 / 12 : .441 /1 : .714 / 16

= .22 : .44 : .0446

= .22 / .22 : .44 / .22 : .044 / .22

= 1 : 2 : .2

1 x 5 : 2 x 5 : .2 x 5

= 5 : 10 : 1

empirical formula of the compound = C₅H₁₀O

Volume of 89.8 mL at 1 .00 atm at 200⁰C

volume of gas at 1 atm and 0⁰C = 89.8 x 273 / 473 mL

= 51.83 mL

51.83 mL weighs .205 g

22400 mL will weigh .205 x 22400 / 51.83 g

= 88.6 g

So molecular weight = 88.6

Let molecular formula be (C₅H₁₀O)ₙ

molecular weight = n ( 5 x 12 + 10 + 16 )

= 86 n

86 n = 88.6

n = 1 approx

So molecular formula is same as empirical formula

C₅H₁₀O is molecular formula .

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