Answer:
He travel for 2 h at the first part and 2 h for the second part.
Explanation:
given information:
business trip's distance, = 214 miles
v₁ = 53 mph
v₂ = 54 mph
t₁ = t
t₂ = 4 - t
now lets find the distance of each speed
s₁ = v₁ t₁ = 53 t₁
s₂ = v₂ t₂ = 54 t₂
= s₁ + s₂
214 = 53 t₁ + 54 t₂
214 = 53t + 54 (4-t)
214 = 53t + 216 - 54 t
t = 216 - 214
= 2 h
t₁ = t = 2 h
t₂ = 4 - t = 4 -2 = 2h
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Can someone pls help us with this question I need the answer too
Acceleration= change in velocity/time=27.8-0/4.8=5.792 ms⁻²
Force= Mass*acceleration=66*5.792=382.25 N
Answer:
D
Explanation:
Hooke's law states the force exerted by a spring is the product of its spring constant and its displacement.
F = kx
Solving for the spring constant:
k = F/x
All the springs are pulled with equal force (the weight of the mass), so the spring with the smallest displacement has the largest spring coefficient.