Explanation:
There are several ways to define acids and bases, but pH and pOH refer to hydrogen ion concentration and hydroxide ion concentration, respectively. The "p" in pH and pOH stands for "negative logarithm of" and is used to make it easier to work with extremely large or small values. pH and pOH are only meaningful when applied to aqueous (water-based) solutions. When water dissociates it yields a hydrogen ion and a hydroxide.
B. It increases the genetic diversity. Sexual reproduction provides genetic diversity because the egg and sperm produced contain different combinations.
The C¬C bond in H₃C¬CF₃ (423 kJ/mol) stronger than that in H₃C¬CH₃ (376 kJ/mol) because of the strong negative inductive effect of fluorine atom
<h3>What is Inductive effect?</h3>
When an electron- withdrawing or an electron- releasing species is allow to introduce to a chain of atoms (generally a carbon chain), according to the species corresponding negative or positive charge is start relayed through the carbon chain by the atoms through which it attached. This makes a permanent dipole to arise in the molecule and is referred to as the inductive effect.
<h3>Types of
Inductive effect</h3>
+ inductive effect
- inductive effect
<h3>What is negative inductive effect?</h3>
Whenever an electronegative atom, like halogen, is introduced to a chain of carbon atoms (generally carbon atoms), this results in unequal sharing of electrons which generates a positive charge which is transmitted through the chain.
This make a permanent dipole to arise in the molecule whereas the electronegative atom get a negative charge and the effect is known as the electron-withdrawing inductive effect, or the -I effect.
Thus, we concluded that the C¬C bond in H₃C¬CF₃ (423 kJ/mol) stronger than that in H₃C¬CH₃ (376 kJ/mol) because of the strong negative inductive effect of fluorine atom.
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Answer:
0.077 M
Explanation:
Molarity is the representation of the solution.
Molarity:
It is amount of solute in moles per liter of solution and represented by M
Formula used for Molarity
M = moles of solute / Liter of solution . . . . . . . . . . (1)
Data Given :
The concentration of half normal (NaCl) saline = 0.45g / 100 g
So,
Volume of Solution = 100 g = 100 mL
Volume of Solution in L = 100 mL / 1000
Volume of Solution = 0.1 L
molar mass of NaCl = 58.44 g/mol
Now to find number of moles of Nacl
no. of moles of NaCl = mass of NaCl / molar mass
no. of moles of NaCl = 0.45g / 58.44 g/mol
no. of moles of NaCl = 0.0077 g
Put values in the eq (1)
M = moles of solute / Liter of solution . . . . . . . . . . (1)
M = 0.0077 g / 0.1 L
M = 0.077 M
So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M
1 ATP = 101.3 kPa
x ATP = 65.78 kPa
cross-multiply
and you'll get x ATP = 0.64936
So, the answer is 0.65 ATP
