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3 years ago

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Grant sprints 50m to the right with an average velocity of 3.0 m/s

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zlopas [31]3 years ago

6 0

I need help with my math

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Knowing the constant g what will the gravitational force between two masses be if the gravitational force between them is 36n an

charle [14.2K]

The gravitational force between two masses is given by:
$F=G \frac{m_1 m_2}{r^2}$
where
G is the gravitational constant
m1 and m2 are the two masses
r is the separation between the two masses

We see that the force is proportional to the inverse of the square of the distance: $F \sim \frac{1}{r^2}$
therefore, if the distance is tripled:
r'=3r
The force decreases by a factor 1/9:
$F \sim \frac{1}{(3r)^2}= \frac{1}{9} \frac{1}{r^2}$

Since the original force was 36 N, the new force will be
$F' = \frac{1}{9} (36 N)= 4 N$

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2 years ago

The way to earn a college diploma is by?

Morgarella [4.7K]

Going to college and passing all your classes

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3 years ago

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The doppler effect is sensitive only to motion along the line of sight. <br> a. True <br> b. False

4vir4ik [10]

Its vey True trust me on this when I say it is

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2 years ago

What are (a) the energy of a photon corresponding to wavelength 6.0 nm, (b) the kinetic energy of an electron with de Broglie wa

dlinn [17]

Explanation:

Given that,

Wavelength = 6.0 nm

de Broglie wavelength = 6.0 nm

(a). We need to calculate the energy of photon

Using formula of energy

$E = \dfrac{hc}{\lambda}$

$E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-9}}$

$E=3.315\times10^{-17}\ J$

(b). We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

$\lambda=\dfrac{h}{\sqrt{2mE}}$

$E=\dfrac{h^2}{2m\lambda^2}$

Put the value into the formula

$E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-9})^2}$

$E=6.709\times10^{-21}\ J$

(c). We need to calculate the energy of photon

Using formula of energy

$E = \dfrac{hc}{\lambda}$

$E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-15}}$

$E=3.315\times10^{-11}\ J$

(d). We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

$\lambda=\dfrac{h}{\sqrt{2mE}}$

$E=\dfrac{h^2}{2m\lambda^2}$

Put the value into the formula

$E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-15})^2}$

$E=6.709\times10^{-9}\ J$

Hence, This is the required solution.

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3 years ago

The nucleus of an atom can have either a positive or negative charge. please select the best answer from the choices provided t

Airida [17]

F - False.

The nucleus of an atom is positively charge.

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3 years ago

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