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Makovka662 [10]
2 years ago
12

TRUE or FALSE: During a collision between objects of different mass, there is a greater force applied to the less massive object

.
Physics
1 answer:
ddd [48]2 years ago
4 0
If they are moving at the same speed then it would be true because the larger object would have more mass and would have more momentum then the smaller object that has less mass! Hope this helps!
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The lung capacity of the average adult is 5.5 liters at the surface and only .37 liters at a depth of 100 meters. The formula to
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What will happen to force?
telo118 [61]

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Why does matter increase in volume when it heats up?
ArbitrLikvidat [17]

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3 years ago
Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 20 cm apart. The sound
krek1111 [17]

Answer:

Explanation:

The path length difference = extra distance traveled

The destructive interference condition is:

\Delta d = (m+1/2)\lambda

where m =0,1, 2,3........

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4 0
2 years ago
a flag of mass 2.5 kg is supported by a single rope. A strong horizontal wind exerts a force of 12 N on the flag. Calculate the
tatuchka [14]
The free-body diagram of the forces acting on the flag is in the picture in attachment.

We have: the weight, downward, with magnitude
W=mg = (2.5 kg)(9.81 m/s^2)=24.5 N
the force of the wind F, acting horizontally, with intensity
F=12 N
and the tension T of the rope. To write the conditions of equilibrium, we must decompose T on both x- and y-axis (x-axis is taken horizontally whil y-axis is taken vertically):
T \cos \alpha -F=0
T \sin \alpha -W=
By dividing the second equation by the first one, we get
\tan \alpha =  \frac{W}{F}= \frac{24.5 N}{12 N}=2.04
From which we find
\alpha = 63.8 ^{\circ}
which is the angle of the rope with respect to the horizontal.

By replacing this value into the first equation, we can also find the tension of the rope:
T= \frac{F}{\cos \alpha}= \frac{12 N}{\cos 63.8^{\circ}}=27.2 N




7 0
3 years ago
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