Remain the same
Explanation:
If the force exerted by the intern is doubled and the distance is halved, the work done by the intern remains the same.
Work done is the force applied to move a body through a distance.
Work done = F x d
where F is the applied force
d is the distance moved
Now;
if:
f = 2f
d =
d
Input the parameter:
Work done = fxd = 2f x
d = fd
The work done will still remain the same
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Boruto because he got naruto
Answer:
20 m/s
Explanation:
initial velocity, u= 25m/s
u has two components. one in horizontal and in one vertical.
so,
u sin theta = vertical component.
=> u sin theta = 25× 4/5
= 20 m/s