Answer:
The number of polarizer needed so transmitted light has at least 12% intensity = 17
Explanation:
Given :
Angle between incident light and optic axis of polarizer = 20°
Given that, the transmission axis of each additional analyzer is rotated 20° relative to the transmission axis of the previous one
According to the malus law,
The intensity of the transmitted light passes through the polarizer is proportional to the square of the cosine of angle between the transmission axis to the optic axis.
⇒
Where, transmitted intensity through polarizer, incident intensity of the light.
Given in question, all the time 20°
By calculation ∴
After 1st polarizer,
∴
Now we need to multiply all the time 0.883 until we get 0.12 (relative 20° angle given in question)
After 17th polarizer we get 0.1205 ≅ 0.12
%
Means we get 12% intensity after 17th polarizing disk.
Answer:
Protons = 50
Mass number = 119
Explanation:
A neutral of tin, Sn, has a Z value of 50 and neutrons are 69.
Z is the atomic number. The atomic number is equal to number of protons or number of electrons in an atom that is neutral i.e:
Z = PROTONS = ELECTRONS
So the number of protons = 50 since Z is 50
>>>>>>>>>>>>>>>¦
The bulk of the mass of an atom is concentrated in the nucleus. To calculate mass number, we simply sum all the elementary particles in the nucleus i.e protons and neutrons. These particles are called the nucleons.
Mass number (A) = P + N
= 50 + 69
= 119
<span>Serdar is interested in psychopathology and wants to go to graduate school and get a doctoral degree in psychology. His choice would most likely lead him toward a career as a </span>Clinical psychologist; doctors which focuses on diagnosing and treating mental, emotional, and behavioral disorders.
<span>The first thing to do here is to figure out how many joules of energy would be produced by your lightbulb in one hour.
As you can see, the conversion factor to use here is
#"1 W" = "1 J"/"1 s"#
This is basically a reminder of the fact that the watt, a unit of power, is defined as an energy of one joule delivered in one second.
Since one hour is known to have #60# minutes, i.e. #60 xx "60 s"#, you will have
#60 xx 60 color(red)(cancel(color(black)("s"))) * "140 J"/(1color(red)(cancel(color(black)("s")))) = "504000 J" = "504 kJ"#
Your next step here will be to use the enthalpy of vaporization of water to figure out how many grams of water would be evaporated by that much heat.
#DeltaH_"vap" = "44.66 kJ mol"^(-1)#
Convert this to kilojoules per gram by using water's molar mass
#44.66 "kJ"/color(red)(cancel(color(black)("mol"))) * (1color(red)(cancel(color(black)("mole H"_2"O"))))/("18.015 g") = "2.479 kJ g"^(-1)#
This means that the mass of water that can be evaporated by #"504 kJ"# of heat will be
#504color(red)(cancel(color(black)("kJ"))) * ("1 g H"_2"O")/(2.497color(red)(cancel(color(black)("kJ")))) = "201.8 g"#
Now, assuming that the sweat is pure water, you can approximate its density to be equal to #"1.0 g mL"^(-1)#. This means that the volume of water that can be evaporated will be
#201.8 color(red)(cancel(color(black)("g"))) * "1 mL"/(1.0color(red)(cancel(color(black)("g")))) = color(green)(bar(ul(|color(white)(a/a)color(black)(2.0 * 10^2 "mL")color(white)(a/a)|)))#
The answer is rounded to two</span>