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3 years ago

Explain how climbing a mountain is similar to hiking from the equator to one of the poles

Physics

2 answers:

4vir4ik [10]3 years ago

7 0

Answer:

Explanation:

SRRY God bless

spin [16.1K]3 years ago

3 0

Climbing an mountain and hiking are similar because both includes walking and climbing and they both are like the same thing

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Two identical waves are destructively interfere. What will happen to the resulting wave?

storchak [24]

Answer:

Because the disturbances are in opposite directions for this superposition, the resulting amplitude is zero for pure destructive interference

Explanation:

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2 years ago

How do you find the direction of displacement?

andreyandreev [35.5K]

You draw a straight line from the start point to the end point. It doesn't matter what route was actually followed for the trip.

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3 years ago

A book has been lifted 1.5 meters into the air giving it 30J of potential energy. How much force was used to lift it

joja [24]

Answer:

Force on the object is 20 N

Explanation:

As we know that work done to raise the book from initial position to final position is known as potential energy stored in it

So here we know that

$U = F.s$

here we know that

U = 30 J

s = displacement = 1.5 m

so we have

$30 = F(1.5)$

$F = 20 N$

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3 years ago

A cannon fires a shell straight upward; 2.3 s after it is launched, the shell is moving upward with a speed of 17 m/s. Assuming

PtichkaEL [24]

Answer:

The speed of the shell at launch and 5.4 s after the launch is 13.38 m/s it is moving towards the Earth.

Explanation:

Let u is the initial speed of the launch. Using first equation of motion as :

$u=v-at$

a=-g

$u=v+gt\\\\u=17+9.8\times 2.3\\\\u=39.54\ m/s$

The velocity of the shell at launch and 5.4 s after the launch is given by :

$v=u-gt\\\\v=39.54-9.8\times 5.4\\\\v=-13.38\ m/s$

So, the speed of the shell at launch and 5.4 s after the launch is 13.38 m/s it is moving towards the Earth.

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3 years ago

An elite tour de france cyclist can maintain an output of 420 watts during a sustained climb. at this output power, how long wou

julia-pushkina [17]

<span>2002 seconds, or 33 minutes, 22 seconds. First, let's calculate how many joules it will take to lift 78 kg against gravity for 1100 meters. So: 78 kg * 9.8 m/s^2 * 1100 m = 840840 kg*m^2/s^2 Now a watt is defined as kg*m^2/s^3, so a division of the required joules should give us a convenient value of seconds. So: 840840 kg*m^2/s^2 / 420 kg*m^2/s^3 = 2002 seconds. And 2002 seconds is the same as 33 minutes, 22 seconds.</span>

7 0

3 years ago