Given that,
Radius of track, r = 50 m
time , t = 9 s
velocity, v = ?
Distance covered by car in one lap around a track is equal to the circumference of the track.
C = 2 π r = 2 * 3.14 * 50
C = 314.159 m
Distance covered by car, s = 314.159 m
Velocity = distance/ time
V = 314.159 / 9
V = 34.9 m/s
The average velocity of car is 34.9 m/s.
Answer:
Explanation:
The law of effect given by Edward Thorndike explains the behavior of child given in the problem . The effect which gives pleasure and satisfying effect are likely to be learnt easily and the effect which creates bad taste are likely to be forgotten easily . actions producing feel good effect are likely to be repeated in future .
Answer: 430 nm
Explanation:
For 257 kJ to dislodge one mole of electrons we need,
275 x 10^3 / 6 x 10^23 = 4.6 x 10^-19
Using Einstein’s relationship between energy, frequency and wavelength
E = hf = h x (c/landa)
Therefore
Landa = h x (c/E) = 6.6 x 10^-34 x (3 x 10^8 / 4.6 x 10^-19 = 4.3 x 10-7 m.
In nm, landa = 430 nm
Answer:
ΔR = 9 s
Explanation:
To calculate the propagation of the uncertainty or absolute error, the variation with each parameter must be calculated and the but of the cases must be found, which is done by taking the absolute value
The given expression is R = 2A / B
the uncertainty is ΔR = |
| ΔA + |
| ΔB
we look for the derivatives
= 9 / B
= 9A (
)
we substitute
ΔR =
ΔA +
ΔB
the values are
ΔA = 2 s
ΔB = 3 s
ΔR =
2 +
3
ΔR = 1.636 + 7.14
ΔR = 8,776 s
the absolute error must be given with a significant figure
ΔR = 9 s
Answer:

Explanation:
As we know by the formula of elasticity that

now we have


Area = 15.2 mm x 19.1 mm

now we also know that force is given as

here we have
stress = Force / Area


now from above formula we have


