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Whitepunk [10]
2 years ago
5

Explain how climbing a mountain is similar to hiking from the equator to one of the poles

Physics
2 answers:
4vir4ik [10]2 years ago
7 0

Answer:

Explanation:

SRRY God bless

spin [16.1K]2 years ago
3 0
Climbing an mountain and hiking are similar because both includes walking and climbing and they both are like the same thing
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A race car makes one lap around a track of radius 50 m in 9.0 s. What is the average velocity? *
Oksi-84 [34.3K]

Given that,

Radius of track, r = 50 m

time , t = 9 s

velocity, v = ?

Distance covered by car in one lap around a track is equal to the circumference of the track.

C = 2 π r = 2 * 3.14 * 50

C = 314.159 m

Distance covered by car, s = 314.159 m

Velocity = distance/ time

V = 314.159 / 9

V = 34.9 m/s

The average velocity of car is 34.9 m/s.

7 0
2 years ago
Kristen, a 3-year-old, enjoys taking baths and is always willing to get into the bathtub. Kristen hates to have her fingernails
SIZIF [17.4K]

Answer:

Explanation:

The law of effect given by Edward Thorndike explains the behavior of child given in the problem . The effect which gives pleasure and satisfying effect are likely to be learnt easily and the effect which creates bad taste are likely to be forgotten easily . actions producing feel good effect are likely to be repeated in future .  

3 0
3 years ago
The energy required to dislodge electrons from sodium metal via the photoelectric effect is 275 kj/mol. What wavelength in nm of
denis23 [38]

Answer: 430 nm

Explanation:

For 257 kJ to dislodge one mole of electrons we need,

275 x 10^3 / 6 x 10^23 = 4.6 x 10^-19

Using Einstein’s relationship between energy, frequency and wavelength

E = hf = h x (c/landa)

Therefore

Landa = h x (c/E) = 6.6 x 10^-34 x (3 x 10^8 / 4.6 x 10^-19 = 4.3 x 10-7 m.

In nm, landa = 430 nm

7 0
3 years ago
Calculate the maximum absolute uncertainty for R if:
Radda [10]

Answer:

ΔR = 9 s

Explanation:

To calculate the propagation of the uncertainty or absolute error, the variation with each parameter must be calculated and the but of the cases must be found, which is done by taking the absolute value

           

The given expression is      R = 2A / B

the uncertainty is                 ΔR = | \frac{dR}{dA} | ΔA + | \frac{ dR}{dB} | ΔB

we look for the derivatives

     \frac{dR}{dA} = 9 / B

     \frac{dR}{dB} = 9A ( - \frac{1}{B^2 } )

we substitute

     ΔR = \frac{9}{B}  ΔA + \frac{9A}{B^2}  ΔB

the values ​​are

     ΔA = 2 s

     ΔB = 3 s

 

     ΔR = \frac{9}{11}   2 + \frac{9 \ 32}{11^2 }  3

     ΔR = 1.636 + 7.14

     ΔR = 8,776 s

the absolute error must be given with a significant figure

     ΔR = 9 s

3 0
3 years ago
Copper has a modulus of elasticity of 110 GPa. A specimen of copper having a rectangular cross section 15.2 mm × 19.1 mm is pull
bearhunter [10]

Answer:

strain = 1.4 \times 10^{-3}

Explanation:

As we know by the formula of elasticity that

E = \frac{stress}{strain}

now we have

E = 110 GPA

E = 110 \times 10^9 Pa

Area = 15.2 mm x 19.1 mm

A = 290.3 \times 10^{-6}

now we also know that force is given as

F = 44500 N

here we have

stress = Force / Area

stress = \frac{44500}{290.3 \times 10^{-6}}

stress = 1.53 \times 10^8 N/m^2

now from above formula we have

strain = \frac{stress}{E}

strain = \frac{1.53 \times 10^8}{110 \times 10^9}

strain = 1.4 \times 10^{-3}

7 0
3 years ago
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