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ValentinkaMS [17]
3 years ago
7

2. Gallium sulfide How do I draw this in Lewis dots?

Chemistry
1 answer:
erma4kov [3.2K]3 years ago
3 0
You just do it with your pencil
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In a high-mass star, hydrogen fusion occurs via the choose one: a. spin-spin interaction. b. proton-proton chain. c. cno cycle.
Lerok [7]

In a high-mass star, hydrogen fusion occurs via the CNO (Carbon-Nitrogen-Oxygen) cycle.

According to the life cycle of a star, there are three main phases in the life of a star: The initial phase (a quick phase), short phase or supergiant phase and death phase or supernova explosion.

the CNO cycle means Carbon-Nitrogen-Oxygen cycle and this process tale place during main sequence phase.

In this phase, hydrogen fuses into helium as a result of six different reaction taking place inside a star.

The first step of the sequence begins when the nucleus of carbon 12 isotope emits gamma rays after capturing a proton and produces nitrogen-13.

This whole cycle is known as stellar nucleosynthesis.

If you need to learn more about Carbon-Nitrogen Cycle click here:

brainly.com/question/13022835


#SPJ4

8 0
2 years ago
A 125 g compound consists of 37% oxygen? What is the mass of oxygen in this compound?
zepelin [54]

19.44%

I think that's the anwer

7 0
3 years ago
Question 1 2.3 kJ is how many J?​
Vinil7 [7]

Answer:

2300J

Explanation:

1 kilojoule is 1000joules so to get how much is 2.3 multiply it with 1000

4 0
2 years ago
……….CO + ………H2 --> C8H18 + ……… H2O
Ksenya-84 [330]

Answer:

8CO + 17H2 = C8H18 + 8H2O

8, 17, 1, 8

5 0
2 years ago
Cyclic compound A has molecular formula C5H10 and undergoes monochlorination to yield exactly three different constitutional iso
RideAnS [48]

Answer:

A: 1,2-dimethylcyclopropane

Explanation:

The possible cyclic structure with formula C₅H₁₀ are shown in the image.

A is a cyclic compound. On monochlorination, A yields 3 products.

To have 3 products on monochlorination, there should be three different carbon atoms.

Considering structure 1, all carbons have same nature, thus only one product will be formed and thus not a structure of A.

Considering structure 2, there are two different carbon atoms, thus two different structure are formed and thus not a structure of A.

Considering structures 3 and 4 , there are four different carbon atoms, thus four products will be formed and either of them are not a structure of A.

Considering structure 5, there are three different carbon atoms,  thus three different structure are formed and thus the A is structure 5.

4 0
3 years ago
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