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4 years ago

What does Kelpers first law of planetary motion imply?

Physics

2 answers:

Andre45 [30]4 years ago

7 0

INERTIA WAS HERE TODAY

sineoko [7]4 years ago

3 0

Kepler's three laws of planetary motion can be stated as follows: (1) All planets move about the Sun in elliptical orbits, having the Sun as one of the foci. (2) A radius vector joining any planet to the Sun sweeps out equal areas in equal lengths of time. (3) The squares of the sidereal periods (of revolution) of the planets are directly proportional to the cubes of their mean distances from the Sun. Knowledge of these laws, especially the second (the law of areas), proved crucial to Sir Isaac Newton in 1684–85, when he formulated his famous law of gravitation between Earth and the Moonand between the Sun and the planets, postulated by him to have validity for all objects anywhere in the universe.

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A sound wave travelling in water at 10.2 m/s has a wavelength of 1.5 m.

Sedbober [7]

Answer:

Frequency of sound wave in water = 6.8 Hz

Explanation:

Given:

Speed of sound wave in water = 10.2 m/s

The wavelength of the sound wave in water = 1.5 m

Find:

Frequency of sound wave in water

Computation:

Frequency = Speed of wave / Wavelength

Frequency of sound wave in water = Speed of sound wave in water / The wavelength of the sound wave in water

Frequency of sound wave in water = 10.2 / 1.5

Frequency of sound wave in water = 6.8 Hz

3 0

3 years ago

An electron, traveling at a speed of 5.90 × 10 6 5.90×106 m/s, strikes the target of an X-ray tube. Upon impact, the electron de

Trava [24]

Answer:

$2.84\cdot 10^{-8} m$

Explanation:

Due to the law of conservation of energy, the energy of the emitted X-ray photon is equal to the energy lost by the electron.

The initial kinetic energy of the electron is:

$K_i = \frac{1}{2}mv_i^2 = \frac{1}{2}(9.11\cdot 10^{-31}kg)(5.90\cdot 10^6 m/s)^2=1.59\cdot 10^{-17}J$

The electrons decelerates to 3/4 of its speed, so the new speed is

$v_f = \frac{3}{4}v_i = \frac{3}{4}(5.90\cdot 10^6 m/s)=4.425\cdot 10^6 m/s$

So the final kinetic energy is

$K_f = \frac{1}{2}mv_f^2=\frac{1}{2}(9.11 \cdot 10^{-31} kg)(4.425\cdot 10^6 m/s)^2=8.9\cdot 10^{-18} J$

So, the energy lost by the electron, which is equal to the energy of the emitted photon, is

$E=K_i - K_f =1.59\cdot 10^{-17} J-8.9\cdot 10^{-18} J=7\cdot 10^{-18} J$

The wavelength of the photon is related to its energy by

$\lambda=\frac{hc}{E}$

where h is the Planck constant and c the speed of light. Substituting E, we find

$\lambda=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{7\cdot 10^{-18} J}=2.84\cdot 10^{-8} m$

4 0

4 years ago

What is the value of g

Mariana [72]

It depends on the environment around you ... the number and size of
the masses around you, and your distance from their center of mass.

If you happen to be on the surface of the Earth, then

   g = 9.8 m/s²
   or
   g = 9.8 newton/kilogram .

It's different on other planets. Be sure to look it up
before you leave, so you'll know what to expect.

5 0

4 years ago

the particles of an object are packed tightly together and are vibrating. when the object is heated, the particles start to move

eimsori [14]

This is an example of state change from solid to liquid.

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3 years ago

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Consider an aircraft powered by a turbojet engine that has a pressure ratio of 12. The aircraft is stationary on the ground, hel

agasfer [191]

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3 0

3 years ago