The statement is false. Sound REQUIRES a material medium
in order to propagate from one place to another..
Answer:
Read this entry from a blog about service dogs.
Lexie, an eight-month-old black Labrador retriever, is sleeping quietly at my feet. I can’t help but think that her soft, velvety ears and alert brown eyes would make her the perfect “doggie model” for pet magazines and pet store ads. However, Lexie will soon have a much more important job to do. In a few months, she will become the loyal companion and service dog for a young man who has been blind since birth. She will help him board public transportation, such as buses, subways, and trains, and she will help him safely cross busy intersections. Lexie will even help the young man avoid obstacles, such as high curbs and low overhangs. Like all dogs in our organization, Lexie has undergone months of specialized training to help a visually impaired person lead an active and independent life.
What is the secondary purpose of this blog?
to inform readers about seeing-eye dogs
to entertain readers with details about Lexie
to persuade readers to train service dogs
to convince readers to adopt Labrador retrievers
Explanation:
The magnitude of the magnetic field on the axis of the ring 5 cm from its center is 143 pT.
The radius of the nonconducting ring is R = 10 cm.
The ring is uniformly charged q = 10 μC.
The angular speed of the ring, ω = 20 rad/s
The ring is x = 5 cm from the center of the ring.
Now,
R = 10 cm = 0.1 m
q = 10.0 μC = 10 × 10⁻⁶ C
x = 5 cm = 0.05 m
The magnetic field on the axis of a current loop is given as:
B = [ μ₀ IR² ] / [4π(x² + R²)^{3/2} ]
Now, I = q / [2π/ω]
So, the magnitude of the magnetic field which is directed away from the center is:
B = [ μ₀ ωqR² ] / [4π(x² + R²)^{3/2} ]
B = [ μ₀ (200) (10 × 10⁻⁶) (0.1)² ] / [4π((0.05)² + (0.1)²)^{3/2} ]
B = 1.43 × 10⁻¹⁰ T
B = 143 pT
Learn more about the magnetic field here:
brainly.com/question/14411049
#SPJ4
Assuming the raindrop was stationary relative to the vertical distance to the ground at the start:
D=0.5at where d is distance, a is acceleration and t is time
D is 300 meters
a is 9.8 meter/sec squared
Solve for t in seconds
t = 61.2 seconds
v=at where v is velocity
a is 9.8 meters per second squared
t is 61.2 seconds
solve for v
v = 600 meters per second.
If it had an initial vertical velocity (v0) at the start :
d= 0.5at+v0t
and
v=at+v0
It would be oraganic matter I think.
