Answer:
Hey
Good question
How can we know if I planet was once inhabited by life? There diferent tequnecs for this. The first would be searching in the soil for fossilized microbes. in June of 19, 1976 Viking 1 was launched on its way to mars to began the search of life els wear. What this little lab did was drill a hole in the marsion terrain and take a sample of its soil to search for microbes or microbe fosles. Sadly it did not find anything. Other technics are to search for ruins on the planet or exoplanet. I do not have much to say about this method because it has never been used.
Hope it helped (i wrote all that).
Spiky Bob your answerer
Below is a picture of Carl Sagan next to the Viking Voyager 1. Obveosly this is just a modal. you could not breathe on mars.
A b c d etc. oh well
Are there any choices perhaps? Gracie
Answer:
Distance between the charges, r = 0.8 meters
Explanation:
Given that,
Charge 1, 
Charge 2, 
Repulsive force between charges, F = 0.66 N
Let r is the distance between charges. The formula for the electrostatic force is given by :
r = 0.8009 meters
or
r = 0.8 meters
So, the distance between the charges i 0.8 meters. Hence, this is the required solution.
<h2>Hello!</h2>
The answer is: B. Kinetic energy
<h2>
Why?</h2>
Since the ball is falling, speed increases because the gravity acceleration is acting. When speed increases, the kinetic energy increases too, so the ball is gaining kinetic energy.
The gravity acceleration is equal to 
, it means that when falling, the ball will increase it's speed 9.81m every second.
We can calculate the kinetic energy by using the following formula:
Where:
Have a nice day!
<h2 />
Answer: 45.3°
Explanation:
Given,
Length of ladder = l
Weight of ladder = w
Coefficient of friction = μs = 0.495
Smallest angle the ladder makes = θ
If we assume the forces in the vertical direction to be N1, and the forces in the horizontal direction to be N2, then,
N1 = mg and
N2 = μmg
Moment at a point A in the clockwise direction is
N2 Lsinθ - mg.(L/2).cosθ = 0
μmgLsinθ - mg.(L/2).cosθ = 0
μmgLsinθ = mg.(L/2).cosθ
μsinθ = cosθ/2
sin θ / cos θ = 1 / 2μ
Tan θ = 1 / 2μ
Substituting the value of μ = 0.495, we have
Tan θ = 1 / 2 * 0.495
Tan θ = 1 / 0.99
Tan θ = 1.01
θ = tan^-1(1.01)
θ = 45.3°
