Answer:
The [H⁺] for this soluton is 2*10⁻³ M
Explanation:
pH, short for Hydrogen Potential and pOH, or OH potential, are parameters used to measure the degree of acidity or alkalinity of substances.
The values that compose them vary from 0 to 14 and the pH value can be directly related to that of pOH by means of:
pH + pOH= 14
In this case, pOH=11.30, so
pH + 11.30= 14
Solving:
pH= 14 - 11.30
pH= 2.7
Mathematically the pH is the negative logarithm of the molar concentration of the hydrogen or proton ions (H⁺) or hydronium ions (H₃O):
´pH= - log [H⁺] = -log [H₃O]
Being pH=2.7:
2.7= - log [H⁺]
[H⁺]= 10⁻² ⁷
[H⁺]=1.995*10⁻³ M≅ 2*10⁻³ M
<u><em>The [H⁺] for this soluton is 2*10⁻³ M</em></u>
<u>Answer:</u> The mass defect for the formation of phosphorus-31 is 0.27399
<u>Explanation:</u>
Mass defect is defined as the difference in the mass of an isotope and its mass number.
The equation used to calculate mass defect follows:
![\Delta m=[(n_p\times m_p)+(n_n\times m_n)]-M](https://tex.z-dn.net/?f=%5CDelta%20m%3D%5B%28n_p%5Ctimes%20m_p%29%2B%28n_n%5Ctimes%20m_n%29%5D-M)
where,
= number of protons
= mass of one proton
= number of neutrons
= mass of one neutron
M = mass number of element
We are given:
An isotope of phosphorus which is 
Number of protons = atomic number = 15
Number of neutrons = Mass number - atomic number = 31 - 15 = 16
Mass of proton = 1.00728 amu
Mass of neutron = 1.00866 amu
Mass number of phosphorus = 30.973765 amu
Putting values in above equation, we get:
![\Delta m=[(15\times 1.00728)+(16\times 1.00866)]-30.973765\\\\\Delta m=0.27399](https://tex.z-dn.net/?f=%5CDelta%20m%3D%5B%2815%5Ctimes%201.00728%29%2B%2816%5Ctimes%201.00866%29%5D-30.973765%5C%5C%5C%5C%5CDelta%20m%3D0.27399)
Hence, the mass defect for the formation of phosphorus-31 is 0.27399
Density:
The density of a substance is equal to the ratio of its mass and volume. In general we can say the density of a substance is mass per unit volume.
Density = mass in g / volume in cubic cm or ml
Given that
Density = 8.92 g/ ml
Mass = 40.0 g
Therefore,
Volume = mass/ density
= 40.0 g/ 8.92 g/ ml
= 4.48 ml
Thus the correct answer is 4.48 ml
Answer:
Eukaryotic
Explanation:
eukaryotic contain both cells