Answer: 0.035 moles FeF3 or 3.5x10-² moles FeF3
Explanation: 1 mole of FeF3 is equal to its molar mass ( 113g FeF3)
4.0g FeF3 x 1 mole FeF3 / 113 g FeF3 = 0.035 moles of FeF3
Answer:- 0.00724 moles.
Solution:- Grams of salicylic acid are given and it asks to calculate the moles.
For the moles, we divide the grams by the molar mass.
Formula of salicylic acid is 
Molar mass = 7(12.01)+6(1.01)+3(16.00)
= 84.07+6.06+48.00
= 138.13 gram per mol
We could make the dimensional analysis set up for showing unit cancellation and have the moles.
= 0.00724 moles
So, there will be 0.00724 moles of salicylic acid in it's 1.00 gram.
<span>They follow mostly from pleistocene climate and topography, so are in general less tightly controlled by bedrock than others. Most terrestrial fossil remains are found either in ponds dating from the receding of previous glaciers or isolated teeth or bone fragments in glacial till. Some important faunas, however, are preserved in pleistocene caves.
i hope this answered your question.</span>
HCl:
<span>
m=48,2g
M=36,5g/mol
n = m/M = 48,2g / 36,5g/mol = 1,32mol
1mol : 4mol
MnO</span>₂ + 4HCl ⇒ MnCl₂ + Cl₂ + 2H₂O
0,86mol : 1,32mol
limiting reagent
0,33 will react
HCl is limiting reagent.
Answer: N = 2.78 × 10^23 atoms
There are N = 2.78 × 10^23 atoms in 70g of Au2cl6
Completed Question:
Calculate the number of gold atoms in a 70g sample of gold(III) chloride . Be sure your answer has a unit symbol if necessary, and round it to significant digits
Explanation:
Given:
Molar mass of Au2cl6 = 303.33g/mol
Mass of Au2cl6 = 70g
Number of moles of Au2cl6 = 70g/303.33g/mol = 0.231mol
According to the chemical formula of Au2cl6,
1 mole of Au2cl6 contains 2 moles of Au
Number of moles of Au = 2 × 0.231mol = 0.462mole
There are 6.022 × 10^23 atoms in 1 mole of an element.
Number of Atom of gold in 0.462 mole of gold is:
N = 0.462 mol × 6.022 × 10^23 atoms/mol
N = 2.78 × 10^23 atoms
