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MakcuM [25]
3 years ago
15

Please answer for me.

Chemistry
1 answer:
jeka943 years ago
4 0

Answer:

54.5%

Explanation:

The percentage composition of oxygen in C₆H₈O₆ can be obtained as follow:

Molar mass of C₆H₈O₆ = (12×6) + (8×1) + (16×6)

= 72 + 8 + 96

= 176 g/mol

Next, there are 6 oxygen atoms in C₆H₈O₆. Therefore the mass of oxygen in C₆H₈O₆ is:

Mass of Oxygen = 16 × 6 = 96 g

Finally, we shall determine the percentage composition of oxygen in C₆H₈O₆ as follow:

Percentage of oxygen =

Mass of Oxygen/mass of C₆H₈O₆ × 100

Percentage of oxygen = 96 / 176 × 100

Percentage of oxygen = 54.5%

Thus, the percentage composition of oxygen in C₆H₈O₆ is 54.5%.

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WORTH 20 POINTS Confirmation bias is where a scientist may change the data to support a certain bias.
Orlov [11]

Answer:

True

Explanation:

Confirmation Bias is the tendency to look for information that supports, rather than rejects, one’s preconceptions, typically by interpreting evidence to confirm existing beliefs while rejecting or ignoring any conflicting data

8 0
2 years ago
In which of the following is most of the water on earth held?
Blizzard [7]
The most water on earth is held by the oceans . 
4 0
3 years ago
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ladessa [460]

Answer:

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3 0
2 years ago
How many grams are in 1.76 x 10^23 atoms of iodine
Mariana [72]

Answer:

\boxed {\boxed {\sf About \ 37.1 \ grams \ of \ iodine }}

Explanation:

To convert from atoms to grams, you must first convert atoms to moles, then moles to grams.

1. Convert Atoms to Moles

To convert atoms to grams, Avogadro's number must be used.

6.022*10^{23}

This number tells us the number of particles (atoms, molecules, ions, etc.) in 1 mole. In this case, the particles are atoms of iodine.

\frac{6.022*10^{23} \ atoms \ I  }{1 \ mol \ I}

Multiply the given number of atoms by Avogadro's number.

1.76*10^{23} \ atoms \ I*\frac{6.022*10^{23} \ atoms \ I  }{1 \ mol \ I}

Flip the fraction so the atoms of iodine will cancel out.

1.76*10^{23} \ atoms \ I*\frac{  1 \ mol \ I}{6.022*10^{23} \ atoms \ I}

1.76*10^{23}* \frac{1 \ mol \ I}{6.022*10^{23} }

Multiply so the problem condenses into 1 fraction.

\frac{1.76*10^{23} \ mol \ I}{6.022*10^{23} }

0.2922617071 \ mol \ I

2. Convert Moles to Grams

Now we must use the molar mass of iodine, which is found on the Periodic Table.

  • Iodine Molar Mass: 126.9045 g/mol

Use this mass as a fraction.

\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}

Multiply this fraction by the number of moles found above.

0.2922617071 \ mol \ I*\frac{ 126.9045 \ g\ I }{ 1 \ mol \ I}

Multiply. The moles of iodine will cancel.

0.2922617071 *\frac{ 126.9045 \ g\ I }{ 1 }

The 1 as a denominator is insignificant.

0.2922617071 *{ 126.9045 \ g\ I }

37.08932581 \ g \ I

3. Round

The original measurement of 1.76*10^23 has 3 significant figures (1, 7, and 6). Therefore we must round our answer to 3 sig figs. For this answer, that is the tenths place.

37.08932581 \ g \ I

The 8 in the hundredth place tells us to round the 0 up to a 1.

\approx 37.1\ g \ I

There is about <u>37.1 grams of iodine </u>in 1.76*10^23 atoms.

5 0
3 years ago
Use the table on the right to calculate each required quantity.
k0ka [10]

a. 35.8 KJ

b. 871 g

c. Fe

..........................................................................................

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