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MakcuM [25]
3 years ago
15

Please answer for me.

Chemistry
1 answer:
jeka943 years ago
4 0

Answer:

54.5%

Explanation:

The percentage composition of oxygen in C₆H₈O₆ can be obtained as follow:

Molar mass of C₆H₈O₆ = (12×6) + (8×1) + (16×6)

= 72 + 8 + 96

= 176 g/mol

Next, there are 6 oxygen atoms in C₆H₈O₆. Therefore the mass of oxygen in C₆H₈O₆ is:

Mass of Oxygen = 16 × 6 = 96 g

Finally, we shall determine the percentage composition of oxygen in C₆H₈O₆ as follow:

Percentage of oxygen =

Mass of Oxygen/mass of C₆H₈O₆ × 100

Percentage of oxygen = 96 / 176 × 100

Percentage of oxygen = 54.5%

Thus, the percentage composition of oxygen in C₆H₈O₆ is 54.5%.

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Explanation:

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2 years ago
Am I correct !<br>Please tell me.<br>If not then pls correct !<br>Thanks​
scZoUnD [109]

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In left hand side of the equation.

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*See the attachment .

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3 years ago
what is the specific latent heat of fusion for a substance that takes 550 kj to melt 14 kg at 262 k? brainly answers
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We know that polar solvent dissolve in polar solvent very perfectly . as diethyl ether is a polar solvent so it have dipole -dipole interaction .

Hence the compound with similar interaction can dissolve in diethyl  ether .

Here , MgBr2  is an ionic compound . there is ion-ion interactions occurs which is not similar to dipole -dipole interaction in diethyl ether .hence the solubility of MgBr2 in diethyl ether is less .

but in case of CH3CH2MgBr there are both polar and nonpolar end .CH3CH2 is the nonpolar end and MgBr is the polar end .

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brainly.com/question/3184550

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