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4vir4ik [10]
3 years ago
7

a mass of 4 kilograms is paced onto a spring snd it stretches 0.2 meters. Why is the spring constant?

Physics
1 answer:
Ray Of Light [21]3 years ago
5 0

Answer:

fgch

Explanation:

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An oscillating object takes 0.10 s to complete one cycle; that is, its period is 0.10 s. what is its frequency f? express your a
Tems11 [23]
<span>10 hertz Hertz is the frequency of oscillation which is the number of oscillations per second. So if something takes 0.10 s per oscillation, divide 1 second by the period to get the frequency. So 1 / 0.10s = 10 1/s = 10 Hertz Therefore the object is vibrating at 10 hertz.</span>
5 0
3 years ago
The energy of microwaves is less than the energy of ultraviolet light. Which comparison of the energies of
adell [148]

Answer:

A. Gamma rays have higher energy than microwaves because gamma rays have shorter wavelengths.

Explanation:

Electromagnetic waves are waves produced by the interaction between both magnetic and electric fields. These waves have some properties that make them to be arranged in a definite form producing an electromagnetic spectrum.

The spectrum has a general property of which as the wavelength of the waves increases, the frequency decreases. And vice versa.

Thus, the energy of the waves increases as the frequency increases.

Gamma rays have higher frequency, but shorter wavelength. While microwaves has lower frequency, but higher wavelength.

8 0
2 years ago
Read 2 more answers
A dockworker applies a constant horizontal force of 80.0 N to a block of ice on a smooth horizontal floor. The frictional force
Tamiku [17]

Answer:

(a) 91 kg (2 s.f.)    (b) 22 m

Explanation:

Since it is stated that a constant horizontal force is applied to the block of ice, we know that the block of ice travels with a constant acceleration and but not with a constant velocity.

(a)

                                                   s \ = \ ut \ + \ \displaystyle\frac{1}{2} at^{2} \\ \\ a \ = \ \displaystyle\frac{2(s \ - \ ut)}{t^{2}} \\ \\ a \ = \ \displaystyle\frac{2(11 \ - \ 0)}{5^{2}} \\ \\ a \ = \ \displaystyle\frac{22}{25} \\ \\ a \ = \ 0.88 \ \mathrm{m \ s^{-2}}

     Subsequently,

                                                  F \ = \ ma \\ \\ m \ = \ \displaystyle\frac{F}{a} \\ \\ m \ = \ \displaystyle\frac{80 \ \mathrm{kg \ m \ s^{-2}}}{0.88 \ \mathrm{m \ s^{-2}}} \\ \\ m \ = \ 91 \mathrm{kg} \ \ \ \ \ \ (2 \ \mathrm{s.f.})

*Note that the equations used above assume constant acceleration is being applied to the system. However, in the case of non-uniform motion, these equations will no longer be valid and in turn, calculus will be used to analyze such motions.

(b) To find the final velocity of the ice block at the end of the first 5 seconds,

                                                    v \ = \ u \ + \ at \\ \\ v \ = \ 0 \ + \ (0.88 \mathrm{m \ s^{-2}})(5 \ \mathrm{s}) \\ \\ v \ = \ 4.4 \ \mathrm{m \ s^{-1}}

     According to Newton's First Law which states objects will remain at rest

     or in uniform motion (moving at constant velocity) unless acted upon by

     an external force. Hence, the block of ice by the end of the first 5

     seconds, experiences no acceleration (a = 0) but travels with a constant

     velocity of 4.4 m \ s^{-1}.

                                                    s \ = \ ut \ + \ \displaystyle\frac{1}{2}at^{2} \\ \\ s \ = \ (4.4 \ \mathrm{m \ s^{-2}})(5 \ \mathrm{s}) \ + \ \displaystyle\frac{1}{2}(0)(5^{2}) \\ \\ s \ = \ 22 \ \mathrm{m}

      Therefore, the ice block traveled 22 m in the next 5 seconds after the

      worker stops pushing it.

4 0
2 years ago
The coefficient of static friction between a 3.00 kg crate and the 35.0o incline is 0.300. What minimum force F must be applied
Yakvenalex [24]

Answer:

So the minimum force is

32.2Newton

Explanation:

To solve for the minimum force, let us assume it to be F (N)

So

F=mgsinA

But

=>>>> coefficient of static friction x (F + mgcosA

=>3 x 9.8 x sin35 = 0.3 x (F + 3 x 9.8 x cos35)

So making F subject of formula

F + 24.0 = 56.2

F = 32.2N

3 0
3 years ago
Wine and cheese are complement goods because they are consumed together. What would we expect to happen to the equilibrium quant
notka56 [123]

Explanation:

As wine and cheese are consumed together,it means that they both are complimentary goods.

As per law of demand,the fall in price of a complimentary good would increase the demand and shift the demand curve of the other to the right.

The equilibrium quantity of cheese would increase and shift to right when the price of wine falls.

8 0
3 years ago
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