An oxidizing agent is reduced. an oxidizing agent is reduced. a. True b. False
1 answer:
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Answer:
The volumetric ratio is 0,71
Explanation:
Let's begin with the equation:
(1)
Where:
Db: Blend Density, Mb: Blend Mass and Vb: Blend Volume
And we know: (2)
Where:
Vg: Gasoline Volume and Vk: Kerosene Volume
Therefore replacing (2) into (1):
(3)
Where:
Dg: Gasoline Density and Dk: Kerosene Density
The specific gravity is defined as:
Therefore:
Where:
Dref: Reference Density
SGb: Blend Specific Gravity
SGg: Gasoline Specific Gravity (which is 0.7 approximately)
SGk: Kerosene Specific Gravity
Replacing these equations into (3) we get:
Replacing with the Specific Gravity data, we obtain:
4K+O2-----------2K2O
Answer:
39.1 °C
Explanation:
Recall the equation for specific heat:
Where q is the heat, m is the mass, c is the specific heat of the substance (in this case water), and delta T is the change in temperature.
You should know that the specific heat of water is 1 cal/g/C.
Using the information in the question:
The final temperature is about 39.1 °C.