Answer:
hello your question is incomplete attached below is the missing equation related to the question
answer : 40.389° , 38.987° , 38° , 39.869° , 40.265°
Explanation:
<u>Determine the friction angle at each depth</u>
attached below is the detailed solution
To calculate the vertical stress = depth * unit weight of sand
also inverse of Tan = Tan^-1
also qc is in Mpa while σ0 is in kPa
Friction angle at each depth
2 meters = 40.389°
3.5 meters = 38.987°
5 meters = 38.022°
6.5 meters = 39.869°
8 meters = 40.265°
Answer:
And replacing in the Carnot efficiency we got:
Explanation:
For this case we can use the fact that the maximum thermal efficiency for a heat engine between two temperatures are given by the Carnot efficiency:
We have on this case after convert the temperatures in kelvin this:
And replacing in the Carnot efficiency we got:
And the maximum power output on this case would be defined as:
Where represent the heat associated to the deposit with higher temperature.
Answer:
a) 229.4281 hp.
b) 262.15 ft3/min.
Explanation:
Given data:
P1 = 14.2 psi
T1 = 60°F = 520° R
P2 = 120 psi
T2 = 500°F = 960° R
volumetric flow rate ( Av1 ) = 1200 ft^3 /min = 20 ft^3 / sec
attached below is the detailed solution
Answer:
The availability of system will be 0.9
Explanation:
We have given mean time of failure = 900 hours
Mean time [to repair = 100 hour
We have to find availability of system
Availability of system is given by
So availability of system
So the availability of system will be 0.9