(263.1 years) x (half-life / 87.7 years) = 3 half-lifes
In 3 half-lifes, (1/2 x 1/2 x 1/2) = 1/8 of the atoms in a sample remain unchanged.
That's 12.5% that remain unchanged.
The other 87.5% of the atoms in the sample have decayed, and changed to either other isotopes of plutonium or into atoms of other elements.
Answer:
2
Explanation:
There are 2 chlorine atoms in AgCl₂. So to balance the equation, there needs to be 2 atoms on the left side as well.
You must apply Archimides' principle.
The barge will sink until the sum of the forces on it equals zero.
The two forces are the weight of the barge (with sand) and the buoyancy force, the force exerted by the liquid (fresh water) on the barge.
Then, weight of the barge with sand = m*g = 600 kg * g
Buoyancy force = density of the fluid * Volume of displaced fulid * g
Then, m*g = density of the fulid * Volume of displaced fluid * g
m*g = df * Vf * g
m = df*Vf => Vf = m/df = 600 kg / 1 000 kg/m^3 = 0.6 m^3
The volume of the displaced fluid equals the volume of the portion of the barge sinked, wich is the area of the rectangular base times the depth to which it sinked>
7m*2m*H = 0.6 m^3 => H = 0.6 m^3 /[14 m^2] = 0.043 m = 4.3 cm
Answer: 4.3 cm
Answer:
0.334 m
Explanation:
The magnetic field due to current in a straight thin wire, , is given by
where is the permeability of free spave with value and is the distance from the wire.
Substituting the values from the question,
Hello!
Work is equal to the change in KE or the negative change in PE. So if e field is directed vertically upward or in positive y direction and our charge is positive it’s going to move in direction of e field so then the work done by the e field is negative because it is losing potential energy the farther it moves upward away from field. Work=qed which is charge*e field*distance travelled.
Hope this helps! Any questions please ask! Thank you!!