To solve this problem it is necessary to apply the concepts related to Sound Intensity. The unit most used in the logarithmic scale is the decibel and mathematically this is expressed as
Where,
= Sound intensity level in decibels
I = Acoustic intensity on the linear scale
Hearing threshold
According to the values, the total intensity is 32 times the linear intensity and the value in decibels is 83dB
So:
Therefore the sound intensity due to one person is 67.948dB
Answer:
2 seconds
Explanation:
The frequency of a wave is related to its wavelength and speed by the equation
where
f is the frequency
v is the speed of the wave
is the wavelength
For the wave in this problem,
v = 2 m/s
So the frequency is
The period of a wave is equal to the reciprocal of the frequency, so for this wave:
This means that the wave takes 4 seconds to complete one full cycle.
Therefore, the time taken for the wave to go from a point with displacement +A to a point with displacement -A is half the period, therefore for this wave: