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Anvisha [2.4K]
2 years ago
8

(Pleaseeee help me) List 3 things you should talk about in a good conclusion?

Chemistry
2 answers:
lions [1.4K]2 years ago
6 0

Answer:

easy, beging sentenice(dont judge spelling), refer to quotes, final thoughts

Explanation:

melamori03 [73]2 years ago
3 0
1) It recaps where you’ve been.
Throughout your essay, you’ve shared experiences, skills and knowledge that have driven you toward who you are today. In your conclusion, remind the admissions team about how all those different elements work in combination to make you a unique candidate for their program.
2) It recaps where you are.
This is an aspect applicants often forget to include. You are at a crucial junction between the past and the future, and this program you’re applying to is the bridge. Recap why this program is an important stepping stone in your career path and how it’s a good fit for you personally.
3) It recaps where you are going.
Most importantly, you must tell the admissions team what your long-term career goal is. The more specific you can be, the better (even if you aren’t 100% sure, it’s best to come off as confident that you know what you want!). For example, rather than just recapping that you want to become a doctor, you can share additional sub-goals, such as wanting to be a doctor who works in low-income, inner city hospitals since you volunteered at those types of facilities before. Or perhaps you plan to go back to the country where you grew up and work as a surgeon there since they are in such short supply.
Bring It Together
Once we bring all three of those elements together, you can see how they link together to form one, solid conclusion. Ideally, your conclusion should be about 4-6 sentences long — not too short but not a long ramble. Below is an example showing how fusing the past (1), present (2) and future (3) together can end your essay on a strong note.
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carbon dioxide at 25 degrees celsius and 101.3 kpa has a density of 1.799 kg/m^3 determine gas constant
dusya [7]

Answer:

Explanation:

Temperature of gas in absolute scale T = 25 + 273 = 298 .

pressure of gas P = 1.013 x 10⁵ N / m²

density D = 1.799 kg / m³

= 1799 g / m³

From gas formula

PV / T = n R Where P is pressure , V is volume and T is absolute temperature , n is no of moles

P / T = n R / V

P / T = m R /M V where m is mass of gas and M is molecular weight .

m / V = D ( density )

P / T = DR/ M  

PM / DT = R

Putting the values

1.013 x 10⁵ x 44  /  (1799 x 298)

R = 8.314.09 J / K mole

5 0
3 years ago
What is the purpose of adding 0. 1% agar to the trypticase nitrate broth when conducting the nitrate reduction test?.
PilotLPTM [1.2K]

Agar is used to assist establish an anaerobic environment that promotes nitrate reduction.

Nitrate Reduction test:

  • The nitrate in the broth is converted to nitrite by organisms that can produce the nitrate reductase enzyme, which can then be further converted to nitric oxide, nitrous oxide, or nitrogen.
  • Anaerobic respiration and denitrification are two processes that can convert nitrate to a variety of compounds.
  • While denitrification only reduces nitrate to molecular nitrogen, anaerobic respiration employs nitrate as the bacterium's final electron acceptor, reducing it to a range of chemicals.
  • The nitrate reduction test is based on the detection of nitrite and its capacity to produce a red precipitate (prontosil), which is a water-soluble azo dye, when it combines with sulfanilic acid to create a complex (nitrite-sulfanilic acid).

Learn more about the Nitrate reduction test with the help of the given link:

brainly.com/question/11181586

#SPJ4

5 0
1 year ago
What is the mass of 0.500 mole of Ba? (Watch sf’s) 68.7 g 137.3 g 68.65 g 69 g
Contact [7]

68.7g

molar mass of Ba(137.327)x (.500)= 68.6635

.500 has 3 sig figs.

8 0
3 years ago
32 g of sulfur will react with 48 g of oxygen to produce 80 g of sulfur trioxide. If 32 g of sulfur and 100 g of oxygen are plac
Lina20 [59]

Answer:

Since the container is consealed, and O2 will no be completely consumed, the total mass of material in the container will be 80 grams SO3+ 52 grams O2 = 132 grams (option B)

Explanation:

Step 1: Data given

Mass of sulfur = 32.00 grams

Mass of oxygen = 48.00 grams

Molar mass of sulfur = 32.07 g/mol

Molar mass of oxygen = 32 g/mol

Molar mass of SO3 = 80.07 g/mol

Step 2: The balanced equation

2S + 3O2 → 2SO3

Step 3: Calculate moles S

Moles S = Mass S / molar mass S

Moles S = 32.0 grams / 32.07 g/mol

Moles S = 0.998 moles

Step 4: Calculate moles O2

Moles O2 = 100.0 grams / 32.0 g/mol

Moles O2 = 3.125 moles

Step 5: Calculate the limiting reactant

For 2 moles S we need 3 moles O2 to produce 2 moles SO3

S is the limiting reactant. It will completely be consumed (0.998 moles)

O2 is in excess, there will be consumed 3/2 * 0.998 = 1.497 moles

There will remain 3.125- 1.497 = 1.628 moles O2

This is 1.628 moles * 32 g/mol = 52.1 grams

Step 6: Calculate moles SO3

For 2 moles S we need 3 moles O2 to produce 2 moles SO3

For 0.998 moles S there will react 0.998 moles SO3

Step 6: Calculate mass SO3

Mass SO3 = moles SO3 * molar mass SO3

Mass SO3 = 0.998 moles * 80.07 g/mol

Mass SO3 = 79.9 grams ≈ 80 grams

There will be produced 80 grams of SO3

Since the container is consealed, and O2 will no be completely consumed, the total mass of material in the container will be 80 grams SO3+ 52 grams O2 = 132 grams (option B)

4 0
3 years ago
To what temperature in kelvin will a 2.3 L balloon have to be heated to expand to a volume of 400 L Assume the initial temperatu
olchik [2.2K]

Answer:

T₂ = 51826.1 K

Explanation:

Given data:

Initial Volume = 2.3 L

Final volume = 400 L

Initial temperature = 25 °C (25+ 273 = 298 K)

Final temperature = ?

Solution:

V₁/T₁ = V₂/T₂

T₂ = V₂ T₁/V₁

T₂ =  400 L . 298 K / 2.3 L

T₂ = 119200 K. L / 2.3 L

T₂ = 51826.1 K

7 0
3 years ago
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