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3 years ago

5

The bulk density of a compacted soil specimen (Gs = 2.70) and its water content are 2060 kg/m^3 and 15.3%, respectively. If the

specimen is soaked in a bucket of water for sev-eral days until it is fully saturated, what should the saturated density be?

1 answer:

yaroslaw [1]3 years ago

4 0

Answer:

the saturated density should be

Explanation:

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$2.

Both tickets cost $1.50
$1.50 x 2 = $3
$5 - $3 = $2

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2 years ago

A DC generator turns at 2000 rpm and has an output of 200 V. The armature constant is 0.5 V-min/Wb, and the field constant of th

WITCHER [35]

Answer:

b. 10A

Explanation:

Using the formula, E= k × r×I

200= 0.5 ×2000×0.02×I

200=20×I

Dividing with 20

I = 200/20= 10A

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3 years ago

Read 2 more answers

Explain why the following scenario fails to meet the criteria for proper reverse engineering.

avanturin [10]

Answer:

he must document or remember the order he took it apart so he put it back together

Explanation:

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2 years ago

Plssssssssssssss Alexi is writing a program which prompts users to enter their age. Which function should she use?

aleksandr82 [10.1K]

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int()

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By elimination, int() is correct.

Hope this helps!

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2 years ago

Refrigerant 134a enters an air conditioner compressor at 4 bar, 20 C, and is compressed at steady state to 12 bar, 80 C. The vol

sleet_krkn [62]

Answer:

$Q=15.7Kw$

Explanation:

From the question we are told that:

Initial Pressure $P_1=4bar$

Initial Temperature $T_1=20 C$

Final Pressure $P_2=12 bar$

Final Temperature $T_2=80C$

Work Output $W= 60 kJ/kg$

Generally Specific Energy from table is

At initial state

$P_1=4bar \& T_1=20 C$

$E_1=262.96KJ/Kg$

With

Specific Volume $V'=0.05397m^3/kg$

At Final state

$P_2=12 bar \& P_2=80C$

$E_1=310.24KJ/Kg$

Generally the equation for The Process is mathematically given by

$m_1E_1+w=m_2E_2+Q$

Assuming Mass to be Equal

$m_1=m_1$

Where

$m=\frac{V}{V'}$

$m=frac{0.06666}{V'=0.05397m^3/kg}$

$m=1.24$

Therefore

$1.24*262.96+60)=1.24*310.24+Q$

$Q=15.7Kw$

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3 years ago