Answer:
<em>Molar mass of the gas is 0.0961 g/mol</em>
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Explanation:
The effusion rate of an unknown gas = 11.1 min
rate of effusion = 2.42 min
molar mass of hydrogen = 1 x 2 = 2 g/m
molar mas of unknown gas = ?
From Graham's law of diffusion and effusion, the rate of effusion and diffusion is inversely proportional to the square root of its molar mass.
from
=
where
= rate of effusion of hydrogen gas
= rate of effusion of unknown gas
= molar mass of H2 gas
= molar mass of unknown gas
substituting values, we have
=
4.587 =
= /4.587
= 0.31
= = <em>0.0961 g/mol</em>
Answer:
4d orbital.
Explanation:
Hello!
In this case, since zirconium's atomic number is 40, we fill in the electron configuration up to 40 as shown below:
Thus, the orbital 4d is partially filled.
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Answer:
We would see 5 peaks. 35Cl the lightest and 37Cl2 the heaviest
Explanation:
The chlorine element has two isotopes (35 Cl and 37 Cl), in the mass spectrum we can observe the m/e of the diatomic molecules. Formed by an atom of chlorine 35 and another of chlorine 35. Or one of Cl 35 and one of Cl 37. Or both of Cl 37.
We can also observe the mass of each separately. That is why we would see 5 peaks.
- Cl = 35 <------------------------- lightest
- Cl = 37
- Cl2 = 35 + 35 = 70
- Cl2 = 35 + 37 = 72
- Cl2 = 37 + 37 = 74 <-------- heaviest
Answer:
Mass of iron = 59.375 gm
Explanation:
Calories ( or joules) are added to the water by the hot steel so at the endpoint they are BOTH at 40 C
The water gains:
4.18 j/g-C * 50 * (40-30 C) = 2090 j
The steel gave up 2090 j going from 120 to 40 C
2090 = .44 j/g-C * m * (120-40) solve fro m = 59.375 gm
Answer:
28 g
Explanation:
The chemical equation of the reaction is given below:
CaCO₃ (s) ⇒ CaO (s) + O₂ (g)
From the chemical equation, 1 mole of CaCO₃ produces 1 mole of CaO.
So, we find the number of moles,n of CaCO₃ in 50 g from
n = m/M where n = number of moles of CaCO₃, m = mass of CaCO₃ and M = molar mass of CaCO₃ = 40 g/mol + 12 g/mol + 3 × 16 g/mol = 52 g/mol + 48 g/mol = 100 g/mol
So, n = m/M
= 50 g/100 g/mol
= 0.5 mol
Since From the chemical equation, 1 mole of CaCO₃ produces 1 mole of CaO, then 0.5 × 1 mole of CaCO₃ produces 0.5 × 1 mole of CaO, which is 0.5 mole of CaCO₃ produces 0.5 mole of CaO.
So, we have 0.5 mol of CaO.
We find the mass of CaO from
n =m'/M' where n = number of moles of CaO = 0.5, m' = mass of CaO and M' = molar mass of CaO = 40 g/mol + 16 g/mol = 56 g/mol
So, m' = nM'
= 0.5 mol × 56 g/mol
= 28 g