Answer:
The value is
Explanation:
From the question we are told that
The velocity is [/tex]
The time taken is
The time taken for contact is
The velocity of the of the car after contact is [/tex]
From the equation of kinematics we have that
Here u = 0 \ m/s since the car is initially motionless
=>
=>
The complete question is missing, so i have attached the complete question.
Answer:
A) FBD is attached.
B) The condition that must be satisfied is for ω_min = √(g/r)
C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).
Explanation:
A) I've attached the image of the free body diagram.
B) The formula for the net force is given as;
F_net = mv²/r
We know that angular velocity;ω = v/r
Thus;
F_net = mω²r
Now, the minimum downward force is the weight and so;
mg = m(ω_min)²r
m will cancel out to give;
g = (ω_min)²r
(ω_min)² = g/r
ω_min = √(g/r)
The condition that must be satisfied is for ω_min = √(g/r)
C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).
Answer:
Explanation:
The energy difference between the energy levels involved in the transition of the electron is directly proportional to the frequency of the emitted photon:
Where h is the Planck constant. The photon's frequency is inversely proportional to its wavelegth:
Here c is the speed of light. Replacing (2) in (1):