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3 years ago

9) An object with a height of 18 cm is placed in front of a converging lens. The image has a

Physics

2 answers:

vovikov84 [41]3 years ago

6 0

Answer:

Explanation:

a) Magnification = image height / object height = -9 / 18 = -0.5

b) Magnification = - image distance / object distance = -0.5

so image distance = 0.5 object distance

1/focal length = 1/image distance + 1/object distance

1/6 = 1/(0.5 object distance) + 1/object distance

object distance = 18.0 cm

c) Image appears behind the lens.

lorasvet [3.4K]3 years ago

5 0

Answer:

Explanation:

mag = ht i/ht o = -9/18 = -1/2

mag = -1/2 = -di/do

do = 2di

put in eqn

1/f = 1/di + 1/do

1/6 = 1/di + 1/2di

2di = 18

do = 18cm

image is behind lens

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