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densk [106]
3 years ago
8

the equilibrium concentrations were found to be [H2O]=0.250 M , [H2]=0.600 M , and [O2]=0.800 M . What is the equilibrium consta

nt for this reaction?
Chemistry
1 answer:
antoniya [11.8K]3 years ago
3 0

Answer:

Keq = 0.217

Explanation:

Let's determine the equilibrium reaction.

In gaseous state, water vapor can be decomposed to hydrogen and oxygen and this is a reversible reaction.

2H₂(g)  + O₂(g)  ⇄  2H₂O (g)         Keq

Let's make the expression for the equilibrium constant

Products / Reactants

We elevate the concentrations, to the stoichiometry coefficients.

Keq = [H₂O]² / [O₂] . [H₂]²

Keq = 0.250² / 0.8 . 0.6² =  0.217

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gizmo_the_mogwai [7]

Answer:

d. they are both involved in the division of somatic cells​

Explanation:

Mitosis and meiosis are both types of cell divisions that occur in the system of living organisms. However, mitosis and meiosis are different in the type and number of daughter cells they give rise to and also where they occur.

Mitosis, which takes place in the SOMATIC OR BODY CELLS of living organisms, give rise to two daughter cells that are genetically identical to their parent cell. On the other hand, meiosis takes place strictly in the CELLS OF REPRODUCTIVE ORGANS, and gives rise to four genetically different daughter cells.

7 0
3 years ago
Dinitrogentetraoxide partially decomposes into nitrogen dioxide. A 1.00-L flask is charged with 0.0400 mol of N2O4. At equilibri
artcher [175]

Answer:

Keq=0.866

Explanation:

Hello,

In this case, the undergone chemical reaction is:

N_2O_42NO_2

In such a way, since 0.0055 mol of N₂O₄ remains in the flask, one infers that the reacted amount (x) was:

x=0.04mol-0.0055mol=0.0345mol

In addition, the produced amount of NO₂ is:

2*0.0345mol=0.069mol

Finally, considering the flask's volume, the equilibrium constant is then computed as follows:

Keq=\frac{(2*0.0345M)^2}{0.0055M}=0.866

Best regards.

6 0
3 years ago
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I hope this helps you :)

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