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MariettaO [177]

3 years ago

10

Q #13 How many moles of MgCl2 are there in 350. g of compound?

1 answer:

Vaselesa [24]3 years ago

8 0

<u>Answer:</u>

3.67 moles

<u>Step-by-step explanation:</u>

We need to find out the number of $MgCl_2$ moles present in 350 grams of a compound.

Molar mass of $Mg$ = 24.305

Molar mass of $Cl_2$ = 35.453

So, one mole of $MgCl_2$ = 24.305 + (35.453 * 2) = 95.211g

1 Mole in 1 molecule of $MgCl_2$ = $\frac{1}{95.211} = 0.0105$

Therefore, number of moles in 350 grams of compound = 0.0105 * 350

= 3.67 moles

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$q=2623.61J$

Now we have to calculate the enthalpy change for the process.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 2626.61 J

n = number of moles of copper sulfate used = $Concentration\times Volume=1M\times 0.050L=0.050mole$

$\Delta H=\frac{2623.61J}{0.050mole}=52472.2J/mole=52.5kJ/mole$

Therefore, the enthalpy change for the process is 52.5 kJ/mole.

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