Answer:
Explanation:
The temperature and amount of gas are constant, so we can use Boyle’s Law.
Data:
Calculations:
A pure substance has "one set of universal properties". This means they have some of the universal properties in common.
<h3>The definition of universal property</h3>
A characteristic that describes some structures up to an isomorphism is known as a universal property in mathematics, more specifically in category theory.
As a result, independent of the construction technique used, some objects can be described using universal properties. For example, one can define polynomial rings as derived from the field of their coefficients, rational numbers as derived from integers, real numbers as derived from integers, and rational numbers as derived from real numbers.
All of these definitions can be made in terms of universal properties. In particular, the concept of universal property offers a simple demonstration of the equality of any real number structures, requiring only that they satisfy the same universal property.
<h3>
What is the universal property of all substances?</h3>
Diamagnetism is a feature that all substances share.
To learn more about Diamagnetism click on the link below:
brainly.com/question/22078990
#SPJ9
Explanation:
Oxidation state of Nitrogen in N2O5 is +5
Answer:
A) 0.065 M is its molarity after a reaction time of 19.0 hour.
B) In 52 hours ![[Co(NH_3)5Br]^{2+}](https://tex.z-dn.net/?f=%5BCo%28NH_3%295Br%5D%5E%7B2%2B%7D)
will react 69% of its initial concentration.
Explanation:
![Co(NH_3)_5(H_2O)_3+[Co(NH_3)5Br]^{2+}(Purple)(aq)+H_2O(l)\rightarrow [Co(NH_3)_5(H_2O)]^{3+}(Pinkish-orange)(aq)+Br^-(aq)](https://tex.z-dn.net/?f=Co%28NH_3%29_5%28H_2O%29_3%2B%5BCo%28NH_3%295Br%5D%5E%7B2%2B%7D%28Purple%29%28aq%29%2BH_2O%28l%29%5Crightarrow%20%5BCo%28NH_3%29_5%28H_2O%29%5D%5E%7B3%2B%7D%28Pinkish-orange%29%28aq%29%2BBr%5E-%28aq%29)
The reaction is first order in :
Initial concentration of = ![[A_o]=0.100 M](https://tex.z-dn.net/?f=%5BA_o%5D%3D0.100%20M)
a) Final concentration of after 19.0 hours= ![[A]](https://tex.z-dn.net/?f=%5BA%5D)
t = 19.0 hour = 19.0 × 3600 seconds ( 1 hour = 3600 seconds)
Rate constant of the reaction = k = 
The integrated law of first order kinetic is given as:
![[A]=[A_o]\times e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA_o%5D%5Ctimes%20e%5E%7B-kt%7D)
![[A]=0.100 M\times e^{-6.3\times 10^{-6} s^{-1}\times 19.0\times 3600 s}](https://tex.z-dn.net/?f=%5BA%5D%3D0.100%20M%5Ctimes%20e%5E%7B-6.3%5Ctimes%2010%5E%7B-6%7D%20s%5E%7B-1%7D%5Ctimes%2019.0%5Ctimes%203600%20s%7D)
![[A]=0.065 M](https://tex.z-dn.net/?f=%5BA%5D%3D0.065%20M)
0.065 M is its molarity after a reaction time of 19.0 h.
b)
Initial concentration of = ![[A_o]=x](https://tex.z-dn.net/?f=%5BA_o%5D%3Dx)
Final concentration of after t = ![[A]=(100\%-69\%) x=31\%x=0.31x](https://tex.z-dn.net/?f=%5BA%5D%3D%28100%5C%25-69%5C%25%29%20x%3D31%5C%25x%3D0.31x)
Rate constant of the reaction = k =
The integrated law of first order kinetic is given as:
t = 185,902.06 s = 
≈ 52 hours
In 52 hours will react 69% of its initial concentration.
